how do I compare columns in a string matrix

I have a given string matrix and I need to check if the word can be read the same from the opposite direction (that it is to say if it is a Palindromes like -live not on evil)

    % 
  wordList = ['civic';'dream';'kayak';'level';...
    'lower';'peace';'radar';'refer';'table';'stats']

if the word is read the same from both direction I have to put 1 in the vector palRes(10,1) if not - I have to put 0 in it...

what I have done:

    % 
  wordList = ['civic';'dream';'kayak';'level';...
    'lower';'peace';'radar';'refer';'table';'stats']
wordList1 = fliplr(wordList)
palRes=zeros(10,1)
for ii= 1:size(wordList,1)
    for jj = 1:size(wordList,2)
    if wordList(ii)== wordList1(ii)

       palRes(ii,jj) = 1
    end
    end
end

but the problem is that the final palRes that I get is a(10,5)matrix instead of (10,1) vec I want to fix this problem inside the loop and not after it! any ideas? thanks!

Answer 1

[Roger Stafford]

Instead of that inner for-loop with the index jj, use the 'all' function:

 palRes(ii) = all(wordList(ii)==fliplr(wordList(ii));

[ilona]

thanks! I am new to matlab - can you explain me what the all function does?

[Roger Stafford]

You can read about it in detail at:

 http://www.mathworks.com/help/matlab/ref/all.html

In your case it is true if each logical element in its vector argument is true.

I have assumed here that wordList(ii) is a vector of string characters. Perhaps it should be written as wordList(ii,:).

[ilona]

I did as you told but still got it wrong

what I did:

    % code
wordList = ['civic';'dream';'kayak';'level';...
    'lower';'peace';'radar';'refer';'table';'stats']
wordList1 = fliplr(wordList)
palRes=zeros(10,1)
for ii= 1:size(wordList,1)
    if all(wordList(ii)==fliplr(wordList(ii)));
       palRes(ii) = 1
    end
end

doing this

palRes =

     1
     1
     1
     1
     1
     1
     1
     1
     1
     1
which is a wrong answer!!!

what have I done wrong :( ?