how do you write a conditional struct?

 채택된 답변

Walter Roberson
Walter Roberson 2013년 11월 18일

1 개 추천

At the beginning start with
data = [];
Then, in each of the error cases, after you disp() the string, add
return
before the "end" of the "if"
if condition
disp('message')
return
end

추가 답변 (1개)

Azzi Abdelmalek
Azzi Abdelmalek 2013년 11월 18일

0 개 추천

Maybe you are asking about if/elseif/else

댓글 수: 4

vishant m.
vishant m. 2013년 11월 18일
i tried using if, but it doesnt work :( can you give a simple example
Matt J
Matt J 2013년 11월 18일
편집: Matt J 2013년 11월 18일
@vishant
Why don't you give an example of what doesn't work and describe what you want to happen instead.
vishant m.
vishant m. 2013년 11월 18일
편집: Azzi Abdelmalek 2013년 11월 18일
function data=test3(n)
if isnumeric(n)==0;
n=([1 2 3 4]); display('input has two many terms or is not a vector');
end
if isvector(n)==0;
n=([1 2 3 4]); display('input has two many terms or is not a vectorl');
end
x=linspace(-5,5,1000);
y=polyval(n,x);
plot(x,y);
q=roots(n);
data=plot(q(imag(q)==0), zeros(sum(imag(q)==0)),'r+');
data= struct('x',x,'p',n,'rp',q,'rpp',q(imag(q)==0),'px',(x));
end
this is the code, you can see the struct. there are 2 if functions at the start, i need the struct to give ans[] when the condition of any of the ifs applies.
Azzi Abdelmalek
Azzi Abdelmalek 2013년 11월 18일
[i need the struct to give ans[] when the condition of any of the ifs applies.] I can't understand what you mean

댓글을 달려면 로그인하십시오.

카테고리

질문:

2013년 11월 18일

댓글:

2013년 11월 18일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by