Error using cos Not enough input arguments. HELP

Hi all,

Can anyone help me with this problem - Error using cos Not enough input arguments.

x=0:0.25:5.*pi;
y=0:0.25:2.*pi;
[x,y]=meshgrid(x,y);
z = cos.*((x).*sin(y)).*((1-3.*cos((y).^2))-(x.^2).*sin((y).^2)).*cos(x);
Error using cos Not enough input arguments.

I'm new to MatLab and I need to plot a contour map using this function but I can't seem to find a way to get rid of the error message. Any help would be much appreciated.

Thanks, Kayn.

Answer 1

[Azzi Abdelmalek]

You missed something in cos.* ,maybe you want

z = cos(x).*((x).*sin(y)).*((1-3.*cos((y).^2))-(x.^2).*sin((y).^2)).*cos(x);

You missed something in cos.

[Gnaneswar Nadh satapathi]

clc
clear all
close all
x=0:0.25:5.*pi; 
y=0:0.25:2.*pi; 
[x,y]=meshgrid(x,y); 
z = (cos(x).*sin(y)).*((1-3.*cos((y).^2))-(x.^2).*sin((y).^2)).*cos(x);
contour(x,y,z)

[Kayn]

Hi Azzi, Thanks for the reply. Although your solution removes the error it changes the equation. It has however highlighted the area where the error is occurring. I basically need the code then for this part of the function - cos(xsin(y))

Your answer gives (cos(x))(xsin(y)) which although removes the error, it doesn't give the correct equation describing the energy interaction I'm working on.

So, does anyone know how to write cos(xsin(y)) in MatLab syntax? I figured it would be cos(x.*sin(y)) or cos.*(x.*sin(y)) but both give the error code.

Cheers

[Azzi Abdelmalek]

The right answer is

cos(x.*sin(y))

[Kayn]

Yes, this works! Many, many thanks Azzi. I now have my contour maps and am trying to make them look nice. Thanks again.

Answer 2

[Diego David Tubay Lozano]

diff(sin^2*([cos^2*(x^2)]))
Error using sin
Not enough input arguments.

help.

[Walter Roberson]

syms x
diff(sin(x)^2 * cos(x^2)^2, x)

ans = 

or possibly you meant

syms x
diff(sin(cos(x^2)^2)^2, x)

ans = 

Answer 3

[Muhammad Syahmi Mohd Shamshul]

5*cos(x)+4.2501-cos*(0.52367-x)

Error using cos

Not enough input arguments.

Error in Secant2 (line 13)

[Walter Roberson]

You have a function named Secant2 that takes at least one parameter, that is named x in the function.

When you ran the function Secant2 you did not provide any parameters at the time of the call. You probably just pressed the big green Run button. When you press the green Run button, MATLAB will run the function without providing any parameters. If you run a function that has a variable (such as x) defined as a parameter, but you run the function without providing a value in that position, then MATLAB will never go hunting around elsewhere looking for an "x" defined somewhere to use as the value in the function. For example,

x = pi/7
y = sin

if sin were defined like

function sx = sin(x)

then MATLAB will never go looking in the workspace to find the pi/7 value to use for the function. If you want a function to use a parameter, then you have to pass the parameter to it.