finding endpoints of a label
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Hi, I have the following matrix. I =
0 0 0 0
0 1 1 1
0 0 0 0
0 0 0 0
0 0 1 0
0 0 1 0
0 0 1 0
[B,L,N,A]=bwboundaries(I,'noholes');
L =
0 0 0 0
0 1 1 1
0 0 0 0
0 0 0 0
0 0 2 0
0 0 2 0
0 0 2 0
idx=find(L==1) endpoints of label 1 are (2,2) and (2,4)
I need to find that endpoints similarly in case of label 2. Thanks endpoints of label 1 are (2,2) and (2,4)
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추가 답변 (2개)
Walter Roberson
2011년 6월 26일
B = bwboundaries(I,'noholes');
xy_1_first = B{1}(1,:);
xy_1_last = B{1}(end,:);
xy_2_first = B{2}(1,:);
xy_2_last = B{2}(end,:);
Andrei Bobrov
2011년 6월 27일
L = bwlabel(I)
I2 = bwmorph(I,'endpoints')
epout = arrayfun(@(i1)find(I2 & L == i1)',1:max(L(:)),'un',0)
example:
I =
0 1 0 1 1 1
1 1 0 0 0 1
1 0 0 0 0 0
1 0 1 1 1 0
0 0 1 0 0 0
0 0 1 0 1 1
0 0 1 0 0 0
0 0 0 0 0 0
1 1 0 0 1 0
0 1 1 0 1 0
0 0 1 0 1 0
0 0 1 0 1 0
0 1 1 0 1 0
0 1 0 0 0 0
0 1 0 1 0 0
0 1 1 1 0 0
0 0 0 0 0 0
>> L = bwlabel(I)
I2 = bwmorph(I,'endpoints');
epout = arrayfun(@(i1)find(I2 & L == i1)',1:max(L(:)),'un',0);
L =
0 1 0 4 4 4
1 1 0 0 0 4
1 0 0 0 0 0
1 0 3 3 3 0
0 0 3 0 0 0
0 0 3 0 5 5
0 0 3 0 0 0
0 0 0 0 0 0
2 2 0 0 6 0
0 2 2 0 6 0
0 0 2 0 6 0
0 0 2 0 6 0
0 2 2 0 6 0
0 2 0 0 0 0
0 2 0 2 0 0
0 2 2 2 0 0
0 0 0 0 0 0
>> epout{5}
ans =
74 91
>>
댓글 수: 3
Mohammad Golam Kibria
2011년 6월 28일
Andrei Bobrov
2011년 6월 28일
I think you can
Mohammad Golam Kibria
2011년 6월 28일
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