if else

i need to compare s=[0 1] with I=[0 0;1 1;1 0;0 1;1 0;0 0; 1 0; 1 1; 0 0;.............................90bits] i want to use counter .can any one help me

Answer 1

[Paulo Silva]

s=[0 1];
I=[0 0;1 1;1 0;0 1;1 0;0 0; 1 0; 1 1; 0 0]
counter=0;
for n=1:size(I,1)
if I(n,:)==s
counter=counter+1;
else
%nothing to be done, just included the else for fun :)
end
end
counter

Alternative just for fun

s=[0 1];
I=[0 0;1 1;1 0;0 1;1 0;0 0; 1 0; 1 1; 0 0]
counter=0;
for n=1:size(I,1)
if I(n,:)~=s
%nothing to be done here :)
else
counter=counter+1;
end
end
counter

[mahaveer hanuman]

i am getting answer as 0.

[Sean de Wolski]

sum(all(bsxfun(@eq,s,I),2))

also for fun!

Answer 2

[Sean de Wolski]

idx = ismember(I,s,'rows'); %row indices of matches
nmatches = sum(idx); %number of matches
row_indices = find(idx); %row numbers of matches

A few of the things you can do...

[mahaveer hanuman]

acutaly i need to use counter so can u help using counter in "if else "

[Sean de Wolski]

Why? nmatches will be the same result as a counted (like in Paulo's below example)

I guess this must be homework...

[Paulo Silva]

I was almost commenting the same you did :) your code is the best way to do it unless it's really homework.