Add all the integers from 1 to n in which the digit m does not appear. m will always be a single digit integer from 0 to 9.
no_digit_sum(10,1) = 44
because 1 and 10 are excluded from the sum and
sum(2:9) = 44
answer to the first test case should be 205
and for third test case should be 558
as question given as summing all digits except the digit mention as 'm'
j'en ai chié
I wonder how could this kinda solution pass the test?!
I will improve this code !
wrong answer,need to use setdiff
2 b | ~ 2 b
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