ある数のベクトルが与えられた場合、そのベクトルの要素の一つが他の要素の二乗であれば true を返し、それ以外の場合は false を返すようなコードを書いてみましょう。
例:
入力が a = [2 3 4] のとき、 出力 b は true になります。
2の2乗は4であり、ベクトル内に2と4の両方が含まれているため、出力は true になります。
- (英語版) Problem 23. Finding Perfect Squares https://www.mathworks.com/matlabcentral/cody/problems/23-finding-perfect-squares/solutions/1330236
Solution Stats
Problem Comments
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2 Comments
David Verrelli
on 11 Nov 2017
This appears to be duplicating an error in the original Problem: according to the problem specification, having an input of [1] should yield a result of "false", as there is no OTHER element to compare the 1 to! You can easily fix this inconsistency by either --- changing your problem specification (mention that you can compare to all vector elements, not just the 'other' elements) or --- by changing the correct result to "false" in your Test Suite.
David Verrelli
on 11 Nov 2017
Please check comments made about the original Problem to avoid duplicating errors or inconsistencies.
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