Problem 1486. Method of Common Differences part-2

Created by G K

Solve Later

{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>This is the inverse problem to</w:t></w:r><w:r><w:t> </w:t></w:r><w:hyperlink w:docLocation=\"http://www.mathworks.com/matlabcentral/cody/problems/1485\"><w:r><w:t>Problem 1485</w:t></w:r></w:hyperlink><w:r><w:t>. Problem 1485 illustrates the method of differences takes a sequence and takes successive differences till it hits a constant. The output was the initial values and the final common difference. This output can be used to regenerate the original sequence. Thus this problem.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Use the initial value and difference vector in the form output in 1485 and generate first n values of the sequence.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Ex: Consider the vector [1 3 2]. The last value '2' is the second order difference and the previous values are the initial values. This generates the sequence [1 4 9 16 25 36 ... ]</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Problem 10) Prev:</w:t></w:r><w:r><w:t> </w:t></w:r><w:hyperlink w:docLocation=\"http://www.mathworks.com/matlabcentral/cody/problems/1485\"><w:r><w:t>1485</w:t></w:r></w:hyperlink><w:r><w:t> Prev:</w:t></w:r><w:r><w:t> </w:t></w:r><w:hyperlink w:docLocation=\"http://www.mathworks.com/matlabcentral/cody/problems/1496\"><w:r><w:t>1496</w:t></w:r></w:hyperlink></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

Solve

Solution Stats

46 Solutions
22 Solvers

Last Solution submitted on Feb 05, 2023

Last 200 Solutions

Problem Comments

Problem Recent Solvers22

Problem Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Problem 1486. Method of Common Differences part-2

Solution Stats

Last 200 Solutions

Problem Comments

Problem Recent Solvers22

Suggested Problems

More from this Author10

Problem Tags

Community Treasure Hunt

Problem 1486. Method of Common Differences part-2

Solution Stats

Last 200 Solutions

Problem Comments

Problem Recent Solvers22

Suggested Problems

More from this Author10

Problem Tags

Community Treasure Hunt

Players