How to find the difference b/w two string time and to convert in to seconds.

In my code time data is as given below. eg. '12.56.13' 12.57.39'. Now how to find the difference b/w the two given time and to convert the obtained value in to seconds. How to pass the obtained seconds to timer. I am having time data of size 45 lake rows. I want efficient way to find the above.

Regards Manu M.J

Answer 1

[Walter Roberson]

datenum() the strings, subtract. To convert the time difference to seconds, multiply by 24*60*60 (number of seconds in a day). To "pass" the obtained seconds to a timer, set the timer StartDelay property to that number of seconds -- and remember to start() the timer.

Answer 2

[Jan]

More efficient than DATENUM:

t1 = '12.56.13';
t2 = '12.57.39';
t1num = [3600, 60, 1] * sscanf(t1, '%d.');
t2num = [3600, 60, 1] * sscanf(t2, '%d.');
tdiff = t2num - t1num;

I do not know what "45 lake rows" are, but you can adjust the above method to all kind of inputs.

[Andrei Bobrov]

if

>> t = ['12.56.13'; '12.57.39'];

then

>> tsec = arrayfun(@(x)[3600 60 1]*sscanf(t(x,:),'%d.'),1:size(t,1)).';

[Manu MJ]

Thank u so much.

It helped me lot.

Answer 3

[Manu MJ]

Datenum('12.36.15') is not functioning. Error is appearing as:

 Error using ==> datenum at 174
DATENUM failed.

Caused by: Error using ==> datevec at 286 Cannot parse date 2.3.4

[Walter Roberson]

datenum('12.36.15','HH.MM.ss')