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Matlab to solve finite difference for Ode

조회 수: 2 (최근 30일)
Ojonile Joseph
Ojonile Joseph 2021년 7월 7일
답변: Viranch Patel 2021년 7월 9일
% Finite difference method
% Approximate the solution of y"=(-2/x)y'+(2/x^2)y+ sin(lnx)/x^2
% for 1<=x<=2 with y(1)=1 and y(2)=2.
p = @(x) (-2/x);
q = @(x) (2/x^2);
r = @(x) (sin(log(x))/x^2);
aa = 1; bb = 2; alpha = 1; beta = 2; n=29;      % h = (bb-aa)/(n+1);   h=0.1
fprintf('   x           w   \n');
h = (bb-aa)/(n+1);
a = zeros(1,n+1);
b = zeros(1,n+1);
c = zeros(1,n+1);
d = zeros(1,n+1);
l = zeros(1,n+1);
u = zeros(1,n+1);
z = zeros(1,n+1);
w = zeros(1,n+1);
x = aa+h;
a(1) = 2+h^2*q(x);
b(1) = -1+0.5*h*p(x);
d(1) = -h^2*r(x)+(1+0.5*h*p(x))*alpha;
m = n-1;
for i = 2 : m
x = aa+i*h;
a(i) = 2+h^2*q(x);
b(i) = -1+0.5*h*p(x);
c(i) = -1-0.5*h*p(x);
d(i) = -h^2*r(x);
end
x = bb-h;
a(n) = 2+h^2*q(x);
c(n) = -1-0.5*h*p(x);
d(n) = -h^2*r(x)+(1-0.5*h*p(x))*beta;
l(1) = a(1);
u(1) = b(1)/a(1);
z(1) = d(1)/l(1);
for i = 2 : m
l(i) = a(i)-c(i)*u(i-1);
u(i) = b(i)/l(i);
z(i) = (d(i)-c(i)*z(i-1))/l(i);
end
l(n) = a(n)-c(n)*u(n-1);
z(n) = (d(n)-c(n)*z(n-1))/l(n);
w(n) = z(n);
for j = 1 : m
i = n-j;
w(i) = z(i)-u(i)*w(i+1);
end
i = 0;
fprintf('%5.4f    %11.8f\n', aa, alpha);
for i = 1 : n
x = aa+i*h;
fprintf('%5.4f    %11.8f\n', x, w(i));
end
i = n+1;
fprintf('%5.4f    %11.8f\n', bb, beta);am trying to run d code but it keeps writing Error: Invalid text character. The text ' ' contains an unsupported non-ASCII whitespace character. Please where am I doing wrong?

답변 (1개)

Viranch Patel
Viranch Patel 2021년 7월 9일
I tried running the code on my machine and it's working fine. You can paste this code to your machine and see if its working. I am attaching the output too. You might be using some wrong character for any particular character which is not supported.
% Finite difference method
% Approximate the solution of y"=(-2/x)y'+(2/x^2)y+ sin(lnx)/x^2
% for 1<=x<=2 with y(1)=1 and y(2)=2.
p = @(x) (-2/x);
q = @(x) (2/x^2);
r = @(x) (sin(log(x))/x^2);
aa = 1; bb = 2; alpha = 1; beta = 2; n=29; % h = (bb-aa)/(n+1); h=0.1
fprintf(' x w \n');
h = (bb-aa)/(n+1);
a = zeros(1,n+1);
b = zeros(1,n+1);
c = zeros(1,n+1);
d = zeros(1,n+1);
l = zeros(1,n+1);
u = zeros(1,n+1);
z = zeros(1,n+1);
w = zeros(1,n+1);
x = aa+h;
a(1) = 2+h^2*q(x);
b(1) = -1+0.5*h*p(x);
d(1) = -h^2*r(x)+(1+0.5*h*p(x))*alpha;
m = n-1;
for i = 2 : m
x = aa+i*h;
a(i) = 2+h^2*q(x);
b(i) = -1+0.5*h*p(x);
c(i) = -1-0.5*h*p(x);
d(i) = -h^2*r(x);
end
x = bb-h;
a(n) = 2+h^2*q(x);
c(n) = -1-0.5*h*p(x);
d(n) = -h^2*r(x)+(1-0.5*h*p(x))*beta;
l(1) = a(1);
u(1) = b(1)/a(1);
z(1) = d(1)/l(1);
for i = 2 : m
l(i) = a(i)-c(i)*u(i-1);
u(i) = b(i)/l(i);
z(i) = (d(i)-c(i)*z(i-1))/l(i);
end
l(n) = a(n)-c(n)*u(n-1);
z(n) = (d(n)-c(n)*z(n-1))/l(n);
w(n) = z(n);
for j = 1 : m
i = n-j;
w(i) = z(i)-u(i)*w(i+1);
end
i = 0;
fprintf('%5.4f %11.8f\n', aa, alpha);
for i = 1 : n
x = aa+i*h;
fprintf('%5.4f %11.8f\n', x, w(i));
end
i = n+1;
fprintf('%5.4f %11.8f\n', bb, beta);
Output:
x w
1.0000 1.00000000
1.0333 1.03067949
1.0667 1.06155254
1.1000 1.09262608
1.1333 1.12390423
1.1667 1.15538887
1.2000 1.18708018
1.2333 1.21897697
1.2667 1.25107701
1.3000 1.28337728
1.3333 1.31587416
1.3667 1.34856355
1.4000 1.38144105
1.4333 1.41450201
1.4667 1.44774163
1.5000 1.48115505
1.5333 1.51473732
1.5667 1.54848354
1.6000 1.58238883
1.6333 1.61644834
1.6667 1.65065735
1.7000 1.68501118
1.7333 1.71950528
1.7667 1.75413522
1.8000 1.78889666
1.8333 1.82378540
1.8667 1.85879736
1.9000 1.89392857
1.9333 1.92917520
1.9667 1.96453354
2.0000 2.00000000

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