How do I solve the double integral determined by the surface z=4x^2-y^2 over the rectangular region created by the coordinates (0,0),(4,0),(0,3) and (4,3) in the xy-plane?

How would I solve this?

Answer 1

[Chunru]

You can do a numerical integration:

z = integral2(@(x, y) 4*x.^2 - y.^2, 0, 4, 0, 3)

z = 220.0000

[trudy rea]

I tried doing the function it is not working properly.

[Walter Roberson]

z = integral2(@(x, y) 4*x.^2 - y.^2, 0, 3, 0, 4)