How to plot the graphs by fixing constants of your choice
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I have this expression as output
C1*exp(-x*(9/(4*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3) + 3/2)) + C2*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2))*cos((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2) - C3*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2))*sin((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2)
How can i plot the graph by fixing constants of my choice
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채택된 답변
DGM
2021년 5월 24일
편집: DGM
2021년 5월 24일
C = [1 2 3] % pick some constants
x = linspace(0,50,100); % pick an interval
y = C(1)*exp(-x*(9/(4*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3) + 3/2)) ...
+ C(2)*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2)) ...
.*cos((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2) ...
- C(3)*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2)) ...
.*sin((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2);
plot(x,y)
or you could do the same thing using symbolic tools
syms x C1 C2 C3
y = C1*exp(-x*(9/(4*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3) + 3/2)) ...
+ C2*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2)) ...
*cos((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2) ...
- C3*exp(x*(9/(8*(37/8 - 10^(1/2))^(1/3)) + (37/8 - 10^(1/2))^(1/3)/2 - 3/2)) ...
*sin((3^(1/2)*x*(9/(4*(37/8 - 10^(1/2))^(1/3)) - (37/8 - 10^(1/2))^(1/3)))/2);
y = subs(y,[C1 C2 C3],[1 2 3]); % specify the constants
fplot(y,[0 50]) % specify the interval
추가 답변 (1개)
KSSV
2021년 5월 24일
You can substitute your value using subs. Read about this function.
Also you can plot for range values using fplot. Read about it.
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