Is there a way to get an 8 x 1 matrix instead of 8 x 3 using dec2bin or any other?

dec2bin (2 ^ n-1: -1: 0) - '0'

[Image Analyst]

Give an example using some specific value of n and show what you got and what you want to get.

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[sawasawa]

Thanks for the link.

This is what I get

n=3
b=dec2bin (2 ^ n-1: -1: 0) - '0'

ans =

     1     1     1
     1     1     0
     1     0     1
     1     0     0
     0     1     1
     0     1     0
     0     0     1
     0     0     0

But I want

     111
     110
     101
     100
     011
     010
     001
     000

Answer 1

[Walter Roberson]

string(dec2bin (2 ^ n-1: -1: 0))

This will be considered an array. The entries will be string objects such as "011". The entries will not be numeric.

[Walter Roberson]

Perhaps you want

n=3

n = 3

b = (dec2bin (2 ^ n-1: -1: 0) - '0')*10.^(n-1:-1:0).'

b = 8×1

111 110 101 100 11 10 1 0

Note that if you do this, then the only way to get the leading zeros is to format it as text again.

Answer 2

[Jan]

If you want 000 as output, remember, that this is not a valid decimal value. If you need the zeros for any reason, you have to stay at the char representation. Simply omit the -'0' part:

n = 3;
b = dec2bin(2 ^ n-1:-1:0)

The cannot be a 8x1 matrix.