Contour Plot of Rosie Function
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Hello,
I am trying to get the same plot as my professor showed in class. He said to use a for loop instead of meshgrid. I keep getting an error that X must not be a scalar. I'm not sure where I'm going wrong. Below is the plot I'm supposed to get followed by my code that is not working.
i=1; j=1;
x1=-1:.01:3;
x2=-1:.01:3;
for a=x1
for b=x2
f(i,j)=100*(a^2-b)^2+(1-a)^2;
j=j+1;
end
j=1;
i=i+1;
end
clf;figure(1)
contour(a,b,f)
댓글 수: 3
Adam Danz
2021년 1월 24일
I'm sure it's based on some dataset, function, or algorithm that our prof must have provided at some point.
답변 (1개)
Star Strider
2021년 1월 24일
Transpose ‘f’, since ‘x1’ and ‘x2’ appear to be the same (otherwise it would also be necessary to reverse their orders in the argument list for the contour call):
i=1; j=1;
% conts=[-1 -.5 0 .5 2 3 3.5 3.6 3.7 3.8 3.9 3.98 4 4.02 4.1 4.2 4.5 5 10 ];
conts = 10.^(-1:1:3);
x1=-1:.01:3;
x2=-1:.01:3;
for a=x1
for b=x2
f(i,j)=100*(a^2-b)^2+(1-a)^2;
j=j+1;
end
j=1;
i=i+1;
end
% clf;
figure(1)
contour(x1,x2,f.',conts, 'ShowText','on', 'LineWidth',1.5)
axis('equal')
.
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