Replacing a cell value in a struct
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Hello,
I have a struct with 4 fields.
One field contains my conditions (3 conditions, named using strings)
Now I want to replace the strings with numbers. How is that possible? So far I could not find anything :( Is this even possible?
Help is much appreciated!
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Image Analyst
2021년 1월 19일
This works:
% Identify what number should replace what character vector.
replacements = {'condi1', 1; 'condi2', 2; 'condi3', 3}
% Make cell array for Conditions
caConditions = {'condi1' 'condi2' 'condi3' 'condi3' 'condi1' 'condi3' 'condi2'}
% Create the whole structure array.
s = struct('subjectnumber', {1 1 1 1 1 1 1}, ...
'condition', caConditions, ...
'rt',{0.12 0.11 0.8 0.9 0.13 0.6 0.12}, ...
'point',{0 40 40 40 20 20 0})
for k = 1 : numel(s)
thisCondition = {s(k).condition}; % Character vector like 'condi1', or 'condi2', etc.
% Compare this condition to the list of them in column 1 of replacements
% and find out which row contains the replacement.
[~, row] = ismember(thisCondition, replacements(:, 1));
% Replace it with the number in column 2
s(k).condition = replacements{row, 2};
end
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Image Analyst
2021년 1월 20일
편집: Image Analyst
2021년 1월 20일
Are you saying that you could have 25 thousand different strings? If so, rather than a look up table like I used, you'd need to use something like sscanf() to parse/extract the number out of the character string.
추가 답변 (2개)
Image Analyst
2021년 1월 19일
Yes. For example to set the "condition" field to the number 5, do this:
yourStruct.condition = 5;
It doesn't matter that it used to be a string.
Attach your structure in a .mat file, or give code to create it, if you still have problems.
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Image Analyst
2021년 1월 19일
AGAIN:
Attach your structure in a .mat file, or give code to create it, if you still have problems.
I need it because I'm not sure how condition is what you showed : 3 character arrays. It can be a character matrix, a string vector, or even a cell array, but I don't know what you have or how you displayed that. Plus answer Bob's questions.
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