# How do i make this code as simple as possible? :(

조회 수: 3 (최근 30일)
Jungwu Kim 2020년 12월 30일
댓글: Jungwu Kim 2020년 12월 31일
final_0 = 0;
final_1 = final(numel(final_0)+1:(floor(numel(final)*1/10))*1);
final_2 = final(floor(numel(final)*1/10)*1+1:floor(numel(final)*1/10)*2);
final_3 = final(floor(numel(final)*1/10)*2+1:(floor(numel(final)*1/10))*3);
final_4 = final(floor(numel(final)*1/10)*3+1:(floor(numel(final)*1/10))*4);
final_5 = final(floor(numel(final)*1/10)*4+1:(floor(numel(final)*1/10))*5);
final_6 = final(floor(numel(final)*1/10)*5+1:(floor(numel(final)*1/10))*6);
final_7 = final(floor(numel(final)*1/10)*6+1:(floor(numel(final)*1/10))*7);
final_8 = final(floor(numel(final)*1/10)*7+1:(floor(numel(final)*1/10))*8);
final_9 = final(floor(numel(final)*1/10)*8+1:(floor(numel(final)*1/10))*9);
final_10 = final(floor(numel(final)*1/10)*9+1:floor(numel(final)));
I think anyone who has studied a little bit can make it simple, but I'm not
For your information, the class of those codes is char.
The size of one data is so large that you want to split it into 10 pieces.
Please let me know, and if you have time, I would like to know if this code can be expressed in loop. :((((((((

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### 채택된 답변

Ameer Hamza 2020년 12월 30일
First, naming variables like final_1, final_2, ... is a bad coding practise: https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval. Always use arrays. In your case, cell arrays are most appropriate.
You can write the code in a single line like this
final = .. % your arrat
final_split = mat2cell(final, 1, numel(final)/10*ones(1,10))
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Ameer Hamza 2020년 12월 31일
편집: Ameer Hamza 2020년 12월 31일
Just use indexing to access each element of the cell array. There is no need to create seperate variables. For example
final_split{1} % access first element
final_split{2} % access second element
..
..
final_split{end} % access last element
Jungwu Kim 2020년 12월 31일
thank you!! god bless you and happy new year~

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### 추가 답변 (1개)

Walter Roberson 2020년 12월 30일
buffer(final, floor(numel(final)/10)).'
Needs the signal processing toolbox.
The final (11th) row will contain 110227 entries only the first two of which will be nonblank. You might want to consider using ceil instead of floor which will get you 10 rows the last of which has 8 padding positions.
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Jungwu Kim 2020년 12월 31일
Thank you so much every time!!! :)

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