traversing an array of elements
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i've the following list of elements as
block 2=10
block 5=16
block 1= 16
block 7=16
block 4= 23
block 6=31
block 3= 31
i.e i've a total of 7 block numbers
the list is in sorted order...
i want to traverse it and find a match between block values like 'block 5', 'block 1' and 'block 7' match
'block 6' and 'block 3' match.. and print these blocks with matching values
how this can be done?
traversing a single list of array of following type i know like
function traverse
clc;
a=[ 1 2 2 3 3 4 4 4 4]
len=length(a)-1;
for i=1:len
if(a(i)==a(i+1))
fprintf('\n%d and %d\n',a(i),a(i+1));
end
end
but to deal with the above list i dont know help me in doing so....
댓글 수: 8
Walter Roberson
2013년 3월 13일
What is the name of your array that is of the form "[s,blockNumber]" ? Are the values in it stored by columns, so Array(2,1) is the second "s" value?
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Jan
2013년 3월 14일
편집: Jan
2013년 3월 14일
A simple approach:
S = [2, 10; 5, 16; 1, 16; 7, 16; 4, 23; 6, 31; 3, 31];
v = unique(S(:, 2));
for iv = 1:length(v)
matchIndex = (S(:, 2) == v(iv));
matchBlock = S(matchIndex, 1)
fprintf('%d:', v(iv));
fprintf(' %d', matchBlock);
fprintf('\n');
end
For larger data sets, histc would be much faster. Search for this command in this forum to find more examples.
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