# how to plot a sequence over a given interval

조회 수: 2(최근 30일)
Connor Wright 2020년 11월 28일
댓글: Connor Wright 2020년 12월 3일
Hello,
After hours upon hours of trying to work this out and a couple of questions here I am having no luck.
I need to plot a seqeunce over a given interval, I have gotten to the point where the sequence is there however I can't find a way around 'vectors must be the same length'
Here is my code...
n = -20:12
x = repmat([5,4,3,2,1],3 15)
linespace(n)
plot(n,x)
I would expect a saw tooth wave looking graph but I get the above mentioned error.
What am I doing wrong? I don't have enough time to play about with the code to try to figure this out as I need to submit a report tomorrow by 11pmand after trying to figure this out for two or three days I am out of ideas.
Any help will be greatly appriciated.
##### 댓글 수: 4표시숨기기 이전 댓글 수: 3
Connor Wright 2020년 11월 28일
Yes, as long as that gives me a graph that looks like a saw tooth wave. Its for a Signal Processing lab report based on MATLAB exercises. I can provide the original data from it if that helps.

댓글을 달려면 로그인하십시오.

### 채택된 답변

Roshan Hingnekar 2020년 12월 1일
In the code mentioned above the length of vector 'n' is 33, the length of vector 'x' is 75, Hence the plot function is giving error.
Use the following code:
n = linspace(-20,12,75);
x = repmat([5,4,3,2,1],3 ,15);
plot(n,x)
xlim([-20 12])
The aboce code should give the saw-tooth output.
##### 댓글 수: 1표시숨기기 없음
Connor Wright 2020년 12월 3일
Thanks for the help, I ended up using
n = linspace(-20,12,length(x))
Whether or not that is the 'correct' way of doing things is another matter.

댓글을 달려면 로그인하십시오.

R2020b

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by