Index exceeds matrix dimensions at buffer function
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Here is what i'm gona trying to do :
- I read a .wav file called tes.wav stored in y
- I try performing 3-level Haar Wavelet Transform on it
- I try to framing the D3 (detail subband level 3)
So i have this following code :
f=wavread('tes.wav','native');
v=[1/sqrt(2) 1/sqrt(2)];
w=[1/sqrt(2) -1/sqrt(2)];
if mod(length(f),2)~=0
f=[f 0];
end
d=length(f);
m=1:d/2;
a1=f(2*m-1).*v(1) + f(2*m).*v(2);
d1=f(2*m-1).*w(1) + f(2*m).*w(2);
d=length(a1);
m=1:d/2;
a2=a1(2*m-1).*v(1) + a1(2*m).*v(2);
d2=d1(2*m-1).*w(1) + a1(2*m).*w(2);
d=length(a2);
m=1:d/2;
a3=a2(2*m-1).*v(1) + a2(2*m).*v(2);
d3=d2(2*m-1).*w(1) + a2(2*m).*w(2);
x=d3(1:length(d3),1);
frame=buffer(x,10);
But i Keep getting error message like this :
??? Index exceeds matrix dimensions.
Error in ==> Project at 32 x=d3(1:length(d3),1);
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채택된 답변
per isakson
2013년 2월 28일
편집: per isakson
2013년 2월 28일
Add the line
size( d3 )
before the line that errors. What does it show? (I guess d3 doesn't have the size you expect.)
Why do you use
x = d3( 1:length(d3), 1 );
and not
x = d3( :, 1 );
?
The error message indicates that the rows of d3 has more elements than the columns.
댓글 수: 3
per isakson
2013년 2월 28일
No, I'm not. However, searching the File Exchange for "haar transform" returned 18 contributions. Many of them with high ratings.
You could open a new question in Answers.
추가 답변 (1개)
Shashank Prasanna
2013년 2월 27일
편집: Shashank Prasanna
2013년 2월 27일
>> clear
and start fresh, There could be a conflict in the name of the variable vs name of the function
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