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Exporting a code from Maple to Matlab

조회 수: 27 (최근 30일)
student_md
student_md 2020년 10월 16일
댓글: Walter Roberson 대략 4시간 전
I use Matlab for numerical calculations.
But I use Maple for symbolic calculations and after the calculations I usually get piecewise functions in my maple codes.
I think the 3d plots in Matlab is very attractive more than Maple plots. So, I want to export piecewise functions in maple to a Matlab code in order to utilize advantages of plots of Matlab.
MAPLE CODE
restart:
u:=1/(1. + exp(x))^2 + 1/(1. + exp(-5.*t))^2 - 0.2500000000 + x*(1/(1. + exp(1 - 5*t))^2 - 1./((1. + exp(-5*t))^2) + 0.1776705118 + 0.0415431679756514*piecewise(0. <= t and t <= 0.5000000000, 1.732050808, 0.) + 0.00922094377856479*piecewise(0. <= t and t <= 0.5000000000, 30.98386677*t - 7.745966692, 0.) + 0.0603742508215732*piecewise(0.5000000000 <= t and t <= 1., 1.732050808, 0.) - 0.00399645630498528*piecewise(0.5000000000 <= t and t <= 1., 30.98386677*t - 23.23790008, 0.)) + (-0.00243051684581302*piecewise(0. <= x and x <= 0.5000000000, 1.732050808, 0.) - 0.000809061198761621*piecewise(0. <= x and x <= 0.5000000000, 30.98386677*x - 7.745966692, 0.) - 0.0152377552205917*piecewise(0.5000000000 <= x and x <= 1., 1.732050808, 0.) - 0.00195593427342862*piecewise(0.5000000000 <= x and x <= 1., 30.98386677*x - 23.23790008, 0.))*piecewise(0. <= t and t <= 0.5000000000, 1.732050808, 0.) + (-0.000433590063316381*piecewise(0. <= x and x <= 0.5000000000, 1.732050808, 0.) - 0.000146112803263678*piecewise(0. <= x and x <= 0.5000000000, 30.98386677*x - 7.745966692, 0.) - 0.00319022339097685*piecewise(0.5000000000 <= x and x <= 1., 1.732050808, 0.) - 0.000477063086307787*piecewise(0.5000000000 <= x and x <= 1., 30.98386677*x - 23.23790008, 0.))*piecewise(0. <= t and t <= 0.5000000000, 30.98386677*t - 7.745966692, 0.) + (-0.00276114805649180*piecewise(0. <= x and x <= 0.5000000000, 1.732050808, 0.) - 0.000933166016624500*piecewise(0. <= x and x <= 0.5000000000, 30.98386677*x - 7.745966692, 0.) - 0.0207984584912892*piecewise(0.5000000000 <= x and x <= 1., 1.732050808, 0.) - 0.00314360556336114*piecewise(0.5000000000 <= x and x <= 1., 30.98386677*x - 23.23790008, 0.))*piecewise(0.5000000000 <= t and t <= 1., 1.732050808, 0.) + (0.000172746997599710*piecewise(0. <= x and x <= 0.5000000000, 1.732050808, 0.) + 0.0000586775450031145*piecewise(0. <= x and x <= 0.5000000000, 30.98386677*x - 7.745966692, 0.) + 0.00136190009033518*piecewise(0.5000000000 <= x and x <= 1., 1.732050808, 0.) + 0.000211410172315387*piecewise(0.5000000000 <= x and x <= 1., 30.98386677*x - 23.23790008, 0.))*piecewise(0.5000000000 <= t and t <= 1., 30.98386677*t - 23.23790008, 0.):
>
plot3d( u,
x=0..1,
t=0..1,
style=surface,
axes=boxed,
colorscheme=[yellow, red]
);
We can transform a maple code to Matlab code by using
with(CodeGeneration):
Matlab(u,resultname="w");
. But The code can' t properly transform to Matlab code.
Could you help me pls
  댓글 수: 2
Rik
Rik 2020년 10월 16일
Is your question how to implement this code in Matlab, or how to successfully convert the code in Maple? As it stands now your question seems better suited to a Maple forum.
student_md
student_md 2020년 10월 16일
How to implement this Maple code in Matlab?

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채택된 답변

Walter Roberson
Walter Roberson 2020년 10월 16일
Optimized version of the calculation:
t1 = exp(x);
t21 = -5 .* t;
t3 = exp(t21);
t5 = exp((1 + t21));
t4 = ((0 <= t & t <= 1/2) .* 1.73205);
t5 = ((0 <= t & t <= 1/2) .* (30.9839 .* t - 7.74597));
t6 = ((1/2 <= t & t <= 1) .* 1.73205);
t7 = ((1/2 <= t & t <= 1) .* (30.9839 .* t - 23.2379));
t6 = (1 + t5).^2;
t2 = 1 ./ t6;
t7 = (1 + t3).^2;
t3 = 1 ./ t7;
t8 = -0.00399646;
t9 = 0.00922094;
t10 = 0.0415432;
t11 = 0.0603743;
t12 = 0.177671;
t13 = ((0 <= x & x <= 1/2) .* 1.73205);
t14 = ((0 <= x & x <= 1/2) .* (30.9839 .* x - 7.74597));
t15 = ((1/2 <= x & x <= 1) .* 1.73205);
t16 = ((1/2 <= x & x <= 1) .* (30.9839 .* x - 23.2379));
t8 = (1 + t1).^2;
t1 = 1 ./ t8;
u1 = -1/4 + (-0.00243052 .* t13 - 0.000809061 .* t14 - 0.00195593 .* t16 - 0.0152378 .* t15) .* t4 + (-0.00043359 .* t13 - 0.000146113 .* t14 - 0.000477063 .* t16 - 0.00319022 .* t15) .* t5 + (-0.00276115 .* t13 - 0.000933166 .* t14 - 0.00314361 .* t16 - 0.0207985 .* t15) .* t6 + t7 .* (0.000172747 .* t13 + 0.0013619 .* t15 + 0.00021141 .* t16 + 5.86775e-05 .* t14) + x .* (t10 .* t4 + t11 .* t6 + t5 .* t9 + t7 .* t8 + t12 + t2 - t3) + t3 + t1;
Unoptimized version of the calculation.
u1 = 1 ./ (1 + exp(x)).^2 + 1 ./ (1 + exp(-(5 .* t))).^2 - 1/4 + x .* (1 ./ (1 + exp((1 - 5 .* t))).^2 - 1 ./ (1 + exp(-(5 .* t))).^2 + 0.177671 + 0.0415432 .* ((0 <= t & t <= 1/2) .* 1.73205) + 0.00922094 .* ((0 <= t & t <= 1/2) .* (30.9839 .* t - 7.74597)) + 0.0603743 .* ((1/2 <= t & t <= 1) .* 1.73205) - 0.00399646 .* ((1/2 <= t & t <= 1) .* (30.9839 .* t - 23.2379))) + (-0.00243052 .* ((0 <= x & x <= 1/2) .* 1.73205) - 0.000809061 .* ((0 <= x & x <= 1/2) .* (30.9839 .* x - 7.74597)) - 0.0152378 .* ((1/2 <= x & x <= 1) .* 1.73205) - 0.00195593 .* ((1/2 <= x & x <= 1) .* (30.9839 .* x - 23.2379))) .* ((0 <= t & t <= 1/2) .* 1.73205) + (-0.00043359 .* ((0 <= x & x <= 1/2) .* 1.73205) - 0.000146113 .* ((0 <= x & x <= 1/2) .* (30.9839 .* x - 7.74597)) - 0.00319022 .* ((1/2 <= x & x <= 1) .* 1.73205) - 0.000477063 .* ((1/2 <= x & x <= 1) .* (30.9839 .* x - 23.2379))) .* ((0 <= t & t <= 1/2) .* (30.9839 .* t - 7.74597)) + (-0.00276115 .* ((0 <= x & x <= 1/2) .* 1.73205) - 0.000933166 .* ((0 <= x & x <= 1/2) .* (30.9839 .* x - 7.74597)) - 0.0207985 .* ((1/2 <= x & x <= 1) .* 1.73205) - 0.00314361 .* ((1/2 <= x & x <= 1) .* (30.9839 .* x - 23.2379))) .* ((1/2 <= t & t <= 1) .* 1.73205) + (0.000172747 .* ((0 <= x & x <= 1/2) .* 1.73205) + 5.86775e-05 .* ((0 <= x & x <= 1/2) .* (30.9839 .* x - 7.74597)) + 0.0013619 .* ((1/2 <= x & x <= 1) .* 1.73205) + 0.00021141 .* ((1/2 <= x & x <= 1) .* (30.9839 .* x - 23.2379))) .* ((1/2 <= t & t <= 1) .* (30.9839 .* t - 23.2379));
Before this you would do the kind of meshgrid() bit that KSSV indicated, and you could surf() the way he did as well.
  댓글 수: 6
Walter Roberson
Walter Roberson 2020년 12월 2일
Unfortunately I recently had a disk crash that affected the drive I was using and the automatic backups of it. I had copied files from it not long before that, but a bunch of the copied files are empty, and I fear that my entire progress on this topic might have vanished.
student_md
student_md 2020년 12월 3일
I would like to state that I am very sorry for the unfortunate crash you have experienced. I hope you can recover all of your data as soon as possible.
Me and a lot of people who need the fantastic Maple code are looking forward to good news from you :)
Best regards.

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추가 답변 (2개)

KSSV
KSSV 2020년 10월 16일
Some thing like this:
x = linspace(0,1) ;
t = linspace(0,1) ;
[x,t] = meshgrid(x,t) ;
u =1./(1. + exp(x)).^2 + 1./(1. + exp(-5.*t)).^2 - 0.2500000000 + x.*(1./(1. + exp(1 - 5*t)).^2 - 1./((1. + exp(-5*t)).^2) .......
+ 0.1776705118 + 0.0415431679756514*piecewise(0. <= t && t <= 0.5000000000, 1.732050808, 0.) .......
+ 0.00922094377856479*piecewise(0. <= t && t <= 0.5000000000, 30.98386677*t - 7.745966692, 0.) .........
+ 0.0603742508215732*piecewise(0.5000000000 <= t && t <= 1., 1.732050808, 0.) ..........
- 0.00399645630498528*piecewise(0.5000000000 <= t && t <= 1., 30.98386677*t ........
- 23.23790008, 0.)) + (-0.00243051684581302*piecewise(0. <= x && x <= 0.5000000000, 1.732050808, 0.).........
- 0.000809061198761621*piecewise(0. <= x && x <= 0.5000000000, 30.98386677*.x .........
- 7.745966692, 0.) - 0.0152377552205917*piecewise(0.5000000000 <= x && x <= 1., 1.732050808, 0.) ........
- 0.00195593427342862*piecewise(0.5000000000 <= x && x <= 1., 30.98386677*x - 23.23790008, 0.)).*piecewise(0. <= t && t <= 0.5000000000, 1.732050808, 0.) ........
+ (-0.000433590063316381*piecewise(0. <= x && x <= 0.5000000000, 1.732050808, 0.) .........
- 0.000146112803263678*piecewise(0. <= x && x <= 0.5000000000, 30.98386677*x - 7.745966692, 0.) .........
- 0.00319022339097685*piecewise(0.5000000000 <= x && x <= 1., 1.732050808, 0.) ...........
- 0.000477063086307787*piecewise(0.5000000000 <= x && x <= 1., 30.98386677*x - 23.23790008, 0.)).*piecewise(0. <= t && t <= 0.5000000000, 30.98386677*t - 7.745966692, 0.) .........
+ (-0.00276114805649180*piecewise(0. <= x && x <= 0.5000000000, 1.732050808, 0.) .......
- 0.000933166016624500*piecewise(0. <= x && x <= 0.5000000000, 30.98386677*x - 7.745966692, 0.)...............
- 0.0207984584912892*piecewise(0.5000000000 <= x && x <= 1., 1.732050808, 0.) .............
- 0.00314360556336114*piecewise(0.5000000000 <= x && x <= 1., 30.98386677*x - 23.23790008, 0.)).*piecewise(0.5000000000 <= t && t <= 1., 1.732050808, 0.) ..............
+ (0.000172746997599710*piecewise(0. <= x && x <= 0.5000000000, 1.732050808, 0.) + 0.0000586775450031145*piecewise(0. <= x && x <= 0.5000000000, 30.98386677*x - 7.745966692, 0.) .............
+ 0.00136190009033518*piecewise(0.5000000000 <= x && x <= 1., 1.732050808, 0.) .......
+ 0.000211410172315387*piecewise(0.5000000000 <= x && x <= 1., 30.98386677*x - 23.23790008, 0.)).*piecewise(0.5000000000 <= t && t <= 1., 30.98386677*t - 23.23790008, 0.) ;
surf(x,t,u)
shading interp
colorbar
If error throws, may be you have to use element by element multiplication .*.
or use element by element divison, ./
Replace and with &&
Or Repalce all && with &.
  댓글 수: 3
Walter Roberson
Walter Roberson 2020년 10월 16일
piecewise() is defined, but it requires the Symbolic toolbox.
Walter Roberson
Walter Roberson 대략 4시간 전
If you take @KSSV's code, but change all of the && to & and then you define
function result = piecewise(condition, truevalue, falsevalue)
if numel(truevalue) == 1
result = repmat(truevalue, size(condition))
else
result = truevalue;
end
if numel(falsevalue) == 1
result(~condition) = falsevalue;
else
result(~condition) = falsevalue(~condition);
end
end
or something similar that accounts for the possibility that the true or false conditions might be expressed as scalars.
There is the possibility that the condition might be a scalar but the truevalue or falsevalue might be non-scalar. In such a case, the result of the piecewise() should be the entire non-scalar truevalue or falsevalue; the above code does not work properly for this case.

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Haitham
Haitham 대략 18시간 전
Thanks everyone

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