필터 지우기
필터 지우기

Solving Explicit integral in symbolic form

조회 수: 1 (최근 30일)
Amit Kadam
Amit Kadam 2012년 12월 2일
Hi all,
I am solving an integral brom beta (which is function of dimensionless alpha) to 1. The function f has x variable and alpha constant. I am trying this with symbolic method. I am expecting solution in terma of alpha. Theta is known. I have followed previous discussions but still I am getting error as 'Explicit integral could not be found'
Please help
clear;clc;
syms alpha positive;
syms x;
theta = 0 ;
beta = (sin (theta) + sqrt( (sin(theta).^2) + (4.*alpha.*(alpha - 1) ) ) ./(2.*alpha))
a = beta;
b = 1;
f =( (x/((alpha.*x.*x)+1-alpha)).^2 -1).^(-1/2)
int(f,x,a,b)

답변 (1개)

Walter Roberson
Walter Roberson 2012년 12월 2일
Can you restrict alpha even further than just "positive" ? The indefinite integral has a number of different cases, sensitive to the value of alpha, and when one tries to use that particular "a", a symbolic division by 0 is created that makes it difficult to resolve the definite integral.
The treatment with unknown alpha also introduces possibly-spurious imaginary quantities.
  댓글 수: 4
Amit Kadam
Amit Kadam 2012년 12월 2일
Thanks Walter, I can not access matlab now. I m sure this will work.
Walter Roberson
Walter Roberson 2012년 12월 3일
I would not count on MuPAD being able to handle the elliptic integrals, but it might be able to.
My system is still trying to find a nicer expression for the integral. So far no meaningful simplifications, other than finding a way to rewrite the single occurrence of EllipticK in terms of EllipticE and EllipticF... not sure if that counts :-(

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Symbolic Math Toolbox에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by