Problem in summation with floor function

조회 수: 4 (최근 30일)
AVM
AVM 2020년 6월 23일
편집: AVM 2020년 6월 24일
I would like to compute the summation involving ''floor function'' as the limit of the sum. Below I have the code. But when I run that some error is apparing which is beyond my understanding. Please somebody help me to solve that issue.
" Error using symengine
Nonnegative integer or a symbol expected.
Error in sym/symsum (line 70)
rSym = mupadmex('symobj::map',fsym.s,'symobj::symsum',x.s,a.s,b.s);
Error in floorfu (line 43)
s23p=symsum(symsum(ss3p.*s2p,l,0,m),k,0,n);"
clc;
syms theta k l p q
W=1.0;
g=0.0001;
lm=0.1;
assume(k>=0);
assume(l>=0);
assume(p>=0);
assume(q>=0);
n=6;
m=6;
t1=floor((k+1)./2); %%%%%%%%%%%%% Floor fun
t2=floor(l./2);
theta=pi./3;
om=sqrt(((W).^2)-(4.*(g.^2)));
mu=sqrt((W+om)./(2.*om));
nu=((W-om)./(2.*g)).*mu;
eta=(((lm)./((2.*g)+W)).*(1+((W-om)./(2.*g)))).*mu;
tau= mu + nu.*cos(2.*theta);
d=k+l-2.*p-2.*q-2;
ag= eta.*cos(theta)./(sqrt(mu.*tau));
s1p=(mu./tau).*((-1).^m).*((1i)^(m+n)).*(2.*eta.*(mu-nu)./(sqrt(2.*mu.*nu))).^(m+n);
s2p=(((nu./2.*eta).*sqrt(mu.*tau)./(mu-nu)).^(k+l)).*factorial(k).*factorial(l).*nchoosek(n,k).*nchoosek(m,l).*exp(1i.*theta.*(k-l));
s3p= ((2./nu.*tau).^(p+q)).*factorial(2.*p + 2.*q +1 -k -l)./(factorial(p).*factorial(q)).*nchoosek(p,k-p).*nchoosek(q,l-q).*exp(-2.*1i.*theta.*(p-q)).*hermiteH(d,ag);
ss3p=symsum(symsum(s3p,q,t2,m),p,t1,n); %%%%%%%%% Actually in this line that error is coming
s23p=symsum(symsum(ss3p.*s2p,l,0,m),k,0,n);
sumout=s1p.*s23p
  댓글 수: 8
Ameer Hamza
Ameer Hamza 2020년 6월 24일
For example, if you have a summation like this
following shows how to use symbolic toolbox or the sum() function using floating-point numbers
syms k
n = 10;
y = k^2*sin(k);
y1 = double(symsum(y, k, 1, n));
kv = 1:n;
y2 = sum(kv.^2.*sin(kv));
AVM
AVM 2020년 6월 24일
편집: AVM 2020년 6월 24일
Thanks for your reply. Okay, with this I must try.

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