필터 지우기
필터 지우기

Multiplying a 2-D array to a specific dimension of a 3-D matrix

조회 수: 2 (최근 30일)
Comrun Yousefzadeh
Comrun Yousefzadeh 2020년 6월 17일
댓글: Ameer Hamza 2020년 6월 18일
Hello. I'm trying to multiply a two dimentioanl array to a specific dimension of a 3-D matrix. For example, A=[2000*2000*72], B=[72*3] and I'm trying to reach
C=[2000*2000*3]. In other words B should be multiplied to the 3rd dimension of A and repeated (element wise) for 2000*2000 points in the first two dimensions. Currently I'm using a loop like this:
for ii=1:size(A,1)
for jj=1:size(A,2)
A1=A(ii,jj,:);
A1=A1(:);
C1=B'*A1; % C1 has dimension of 3*1
C2=D*C1; %D is a 3-3 matrix therefore, C2 has the same dimension as C1
C(ii,jj,:)=C2(:,1);
end
end
Is there a simple way to write this? I would rather avoid complications using "for loop".
Thanks, Cameron

채택된 답변

Ameer Hamza
Ameer Hamza 2020년 6월 18일
편집: Ameer Hamza 2020년 6월 18일
Try something like this
A = rand(100, 100, 72);
B = rand(72, 3);
A_C = mat2cell(A, ones(size(A,1),1), ones(size(A,2),1), size(A,3));
C = cell2mat(cellfun(@(x) {reshape(squeeze(x).'*B, 1, 1, [])}, A_C));
Although I guess that the solution using for-loop will be much faster.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by