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Determine the percentage of black pixels within a circle

조회 수: 2(최근 30일)
Vance Blake
Vance Blake 2020년 5월 18일
편집: Vance Blake 2020년 5월 18일
Hello, I am trying to determine the total number of pixels within the blue circle (radius = 80 dimensionless units) and the percentage of them that are black. I have multiple files that I would like to analyze, and I wanted to code a way to read in each picture in the folder one by one and then store each image name with its coresponding percentage of black pixels in a matrix. The image sizes are not standardized since they were created using the snipping tool
I have tried to implement the methods in shown in the solution links but each one is more piece of what I need and Im struggling to put them all together. Any help would be greatly appreciated.
pathname = uigetdir;
allfiles = dir(fullfile(pathname,'*.png'));
image_percent = [];
for i=1:size(allfiles,1)
x=imread([pathname '\\' allfiles(i).name]);
image_percent=[image_percent; x]; % storage
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Vance Blake
Vance Blake 2020년 5월 18일
Hi darova the center of the blue circle is the coordinates [0,0] on the plot. I don't know how that translates to the pixels of the png file itself though

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Image Analyst
Image Analyst 2020년 5월 18일
Please post the original image, not a screenshot. Is the actual image a real gray scale image, or is it that RGB computer graphics diagram? Then, how are you getting the black and white (binary, logical) image from the original image?
Anyway, once you have the image segmented so that you have a mask with only black pixels and white pixels, then you can use sum() and nnz() to do the count. Assume circleMask is the mask of the overall, outer circle, and mask is your segmented, binary image of stuff inside you're interested in, then
numPixelsInCircleMask = sum(circleMask(:))
numWhitePixelsInMask = nnz(mask)
numBlackPixelsInMask = nnz(~mask) % or (numPixelsInCircleMask - numWhitePixelsInMask)
whiteAreaFraction = numWhitePixelsInMask / numWhitePixelsInMask
blackAreaFraction = 1 - whiteAreaFraction
  댓글 수: 2

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