How to compare pair of rows in a column and report it in hexadecimal format

Hello,

I have a 512x1 matrix (512 rows and 1 column)

The value of ROW1 should be compared with ROW2, similarly ROW3 with ROW4, etc. I have to compute this 256-bit response and report it in hexadecimal format assuming; if ROW1 > ROW2 then 1 & if ROW2 > ROW1 then 0

In this way I will get 256x1 from this.

Please advise!

Answer 1

[Mohammad Sami]

data = rand(512,1);
oddrows = data(1:2:end);
evenrows = data(2:2:end);
response1 = oddrows > evenrows;
response2 = evenrows > oddrows;

response1 = char(response1' + '0');
response2 = char(response2' + '0');

% download bin2hex function from matlab file exchange
% https://www.mathworks.com/matlabcentral/fileexchange/1975-bin2hex

response1hex = bin2hex(response1);
response2hex = bin2hex(response2);

[Farhan K]

where should I keep the downloaded bin2hex function file?

Also is there any other alternative of this function?

[Farhan K]

after comparing there will only 1 result: 256x1 matrix

[Mohammad Sami]

You can place the file in your working directory so its accessible to your code. There maybe other alternatives on file exchange or you can write your own.

The result is 256 logical vector (binary). So you need the bin2hex function to convert it to hex.

[Farhan K]

Your code is giving me response1hex and response2hex. But I need output which is 256x1 matrix.

I was trying below code:

oddrows = MeanofAvg(1:2:end);
evenrows = MeanofAvg(2:2:end);
if oddrows > evenrows
    oddrows = 1;
else
    oddrows = 0;
end

I am stuck here, dont know how to proceed further.

[Mohammad Sami]

response1 = oddrows > evenrows

this would give u the 256 x 1 logical vector

value would be 1 where oddrow is greater then even row and 0 otherwise.

[Mohammad Sami]

If you want the values you can do the additional step

response1 = oddrows > evenrows;
values = zero(length(response1),1);
values(response1) = oddrows(response1);
values(~response1) = evenrows(~response1);