필터 지우기
필터 지우기

Solve least square error optimization

조회 수: 2 (최근 30일)
Kees de Kapper
Kees de Kapper 2019년 12월 2일
댓글: Adam Danz 2019년 12월 3일
Dear all,
I've got the following optimization problem:
D1 = F1 (d1), D2 = F2(d2), D3 = F3(d3) are seperate functions for three different measurements
d1=ds1*x; d2=ds2*x; d3=ds3*x; ds123 is the sample measurement, and the x is the correction of the error.
To find the optimal correction value x, the following should be minimized:
min( (D1-D2)^2 + (D2-D3)^2 + (D3-D1)^2 , x)
This might be done using an optimization routine but becomes very slow if the number of measurements increases (in case of an image).
Is there a straight forward way to perfom, which is considerably faster?
many thanks in advance.
all the best,
Kees
  댓글 수: 5
Kees de Kapper
Kees de Kapper 2019년 12월 3일
Thanks for considering my question.
This is basically my code:
function Main(ImgData)
% FuncModel and ParameterSet are known variables
for d = 1:3
F{d} = cfit(FuncModel, ParameterSet{d});
end;
x = ones(size(ImgData, 1),size(ImgData, 2));
x0 = 1;
for n1 = 1:size(ImgData, 1)
for n2 = 1:size(ImgData, 2)
[x(n1,n2),fval,exitflag,output] = fmincon(@(x)evalfnc(x, F,ImgData(n1,n2)), x0, [],[],[],[], 0.5, 1.5, []);
end;
end;
function v = evalfnc(x, F, ImgPixel)
for d=1:3
v(d) = F{d}(x*ImgPixel(d));
end;
v = (v(1)-v(2)).^2 + (v(2)-v(3)).^2 + (v(3)-v(1)).^2;
Indeed "x" is a scalar value, d1,2,3 are scalar values per measurement but stored as an array (three channel image).
Adam Danz
Adam Danz 2019년 12월 3일
Any chance you could attach a mat file with all the variables needed to run the code? It's just a lot faster for us mortals if we can step through the code rather than imagining it.

댓글을 달려면 로그인하십시오.

답변 (0개)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by