I got this Error :Matrix dimensions must agree
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Q1: When i input this formula ; f=(4/pi)*sum((1./n)*sin(2*pi*n.*t)) I got this error: Matrix dimensions must agree
Where n=1:2:401 and t=linspace(-0.5,0.5,250)
Q2: f=1/pi+0.5*sin(pi*tau)-2/pi*(cos(pi*n'*tau)/n'.^2-1) tau=linspace(-0.5,0.5,250); n=2:2:106; i get the same error !
Please correct it for me. And show me where are the mistakes
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답변 (3개)
Andrei Bobrov
2012년 9월 18일
편집: Andrei Bobrov
2012년 9월 18일
one way
%W1:
n = (1:2:401).';
t = linspace(-0.5,0.5,250);
f = 4/pi*sum(bsxfun(@times,1./n,sin(2*pi*n*t)));
%W2:
n = (2:2:106).';
tau = linspace(-0.5,0.5,250);
f = 1/pi+bsxfun(@minus,0.5*sin(pi*tau),2/pi*(bsxfun(@rdivide,cos(pi*n*tau),n.^2)-1));
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Jan
2012년 9월 18일
Mohammed has written [MOVED from answer to comment section]:
But i need 250 variables for t
Jan
2012년 9월 18일
for the expression n .* t the variables n and t must have the same size. Perhaps you want a matrix like, e.g. created by a dyadic product:
n(:) * t
But as long as you do not specify this, n .* t is simply a bug, when the sizes differ or non of them is a scalar.
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Mohammed
2012년 9월 18일
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Jan
2012년 9월 18일
편집: Jan
2012년 9월 18일
Please, Mohammed, do not post comments to answers as answer, but as comment. When you claim, that a suggested method "does not work", be so kind to show the code, the error message or an explanation of the difference between your expectation and the results.
Of course my suggestion will "not work", because I told you, that there is a bug in your code or that you at least did not tell us, what you want to achieve exactly enough. How could this be "working"?!
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