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Why are condition2 condition3 and condition4 not logical?

조회 수: 2 (최근 30일)
zhenyu zeng
zhenyu zeng 2019년 7월 22일
댓글: Image Analyst 2019년 7월 23일
a=0.336;
Ta=9.476;
Te=1.208;
Tw=1.498;
eqh=[0.661;0.619;0.568];
ex=[-1.24;-1.346;-1.441];
en=-ex;
ey=[0.376;0.705;0.968];
eqx=[-0.309;-0.357;-0.392];
eh=[1.594;1.583;1.545];
eyqh=[0.642;0.78;0.897];
a0=a*Ta*Te^2;
r = -100:1:100;
[bt,Td]=meshgrid(r);
i=1;
figure('Name','Stable');
Kp=1./bt;
exqh(i)=en(i).*eqh(i)+eqx(i).*eh(i);
Ki=1./(bt.*Td);
a1=Ta.*Tw.*eqh(i)+a.*Te^2.*en(i)+a.*Te^2.*ey(i).*Kp;
a2=a.*Te^2.*Ki*ey(i)+Ta+Tw.*exqh(i)-eyqh(i).*Kp.*Tw;
a3=en(i)+ey(i).*Kp-eyqh(i).*Ki.*Tw;
a4=ey(i).*Ki;
condition1 =a1>0; output = ones(length(r));condition2=zeros(size(condition1));condition3=zeros(size(condition1));condition4=zeros(size(condition1));
for j=1:numel(a1)
condition2(j)=det([a1(j) a0;a3(j) a2(j)])>0;
condition3(j) =det([a1(j) a0 0;a3(j) a2(j) a1(j);0 a4(j) a3(j)])>0;
condition4(j)=det([a1(j) a0 0 0;a3(j) a2(j) a1(j) a0;0 a4(j) a3(j) a2(j);0 0 0 a4(j)])>0;
end
output(~(condition1 & condition2 & condition3 & condition4)) = 0;
imshow(output, 'xdata', r, 'ydata', r);
axis on;
Why are condition2 condition3 and condition4 not logical?

채택된 답변

Image Analyst
Image Analyst 2019년 7월 22일
You defined them to be doubles by instantiating them with the zeros() function. Try using false() instead of zeros():
condition2 = false(size(condition1));
condition3 = false(size(condition1));
condition4 = false(size(condition1));
  댓글 수: 2
zhenyu zeng
zhenyu zeng 2019년 7월 23일
Thanks, I know now.l
Image Analyst
Image Analyst 2019년 7월 23일
Please, can you then "Accept this answer" by clicking on that link on this page? Thanks in advance.

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