Creating Timetables: Error Message in SampleRate

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FW
FW 2019년 4월 18일
댓글: Peter Perkins 2019년 5월 3일
Hello, I am trying to use a suggested function to generate a timetable with a sampling frequency of 200 Hz.
tt = timetable(rand(12,1),'SampleRate', 200)
I get an error: Invalid parameter name: SampleRate. This is MATLAB 2017b.
How do we get the desired sample rate?
Thanks.

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Adam Danz
Adam Danz 2019년 4월 18일
편집: Adam Danz 2019년 4월 19일
Here's a link to the 2017b documentation for timetable().
You'll see that there is no 'SampleRate' property. That property appeared first in r2018b.
Here's how to achive your example for releases before and after 2018b.
% 2018b or more recent
data = rand(12,1);
sampleRate = 200; %hz
tt = timetable(data,'SampleRate', sampleRate);
% prior to 2018b
timeSamples = seconds(0 : 1/sampleRate : (size(data)-1)/sampleRate);
tt = timetable(timeSamples', data);
  댓글 수: 2
FW
FW 2019년 4월 19일
Thank you. I will try to update to 2018b.
Peter Perkins
Peter Perkins 2019년 5월 3일
Adam is right, but usually this
seconds((0:(size(data)-1))/sampleRate)
is better numerically.

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