# system of 5 eq and 5 uknowns, FSOLVE error

조회 수: 1 (최근 30일)
gorilla3 . 2019년 4월 15일
댓글: Star Strider . 2019년 4월 16일
Hi,
I have an error in the initial condition (B0) estimation but don't know how to solve it. How does one choose the initial parameters of the solution? I only gave it random values... here's the code:
syms Rsa Vsa P3 q Psa real
e1= Rsab/(Vsa/Vsab)^2 -Rsa;
e2= Csa*(Psa-Pic) -Vsa;
e3= q*Rlv+Pvb-P3;
e4= (Psa-P3)/(Rsv+0.5*Rsa+Rnet) -q;
e5= ABP-q*(Rla+0.5*Rsa)-Psa;
Eqnsfcn = matlabFunction([e1, e2, e3, e4, e5], 'Vars',{[Rsa, Vsa, P3, q, Psa]});
B0 = rand(1,5)*100; %initial parameters
[B,fval] = fsolve(@(b)Eqnsfcn(b(1),b(2),b(3),b(4),b(5)), B0);
Bc = num2cell(B);
[Rsa, Vsa, P3, q, Psa] = Bc{:}
this is the error I get is below. Could you please help me get real solutions of these equations? Thanks!
Error using
symengine>@(in1)[-in1(:,1)+1.0./in1(:,2).^2.*2.145016313856e-4,in1(:,5).*3.7e-8-in1(:,2)-3.7e-7,-in1(:,3)+in1(:,4).*1.8928e6+6.0,-in1(:,4)-(in1(:,3)-in1(:,5))./(in1(:,1).*(1.0./2.0)+9.024393684230502e15),-in1(:,5)-in1(:,4).*(in1(:,1).*(1.0./2.0)+1.352e6)+1.0e2]
Too many input arguments.
Error in eqsystem_O2_15_04_19_v1>@(b)Eqnsfcn(b(1),b(2),b(3),b(4),b(5))
Error in fsolve (line 242)
fuser = feval(funfcn{3},x,varargin{:});
Error in eqsystem_O2_15_04_19_v1 (line 48)
[B,fval] = fsolve(@(b)Eqnsfcn(b(1),b(2),b(3),b(4),b(5)), B0);
Caused by:
Failure in initial objective function evaluation. FSOLVE cannot continue.

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### 채택된 답변

Star Strider 2019년 4월 15일
There are a few errors in your posted code.
Corrected:
syms Rsa Vsa P3 q Psa Rsab Vsab Csa Pic Rsv Rlv Pvb Rnet ABP Rla real
Rsab = V.Rsab;
Vsab = V.Vsab;
Csa = V.Csa;
Pic = V.Pic;
Rsv = V.Rsv;
Rlv = V.Rlv;
Pvb = V.Pvb;
Rnet = V. Rnet;
ABP = V.ABP;
Rla = V.Rla;
e1= Rsab/(Vsa/Vsab)^2 -Rsa;
e2= Csa*(Psa-Pic) -Vsa;
e3= q*Rlv+Pvb-P3;
e4= (Psa-P3)/(Rsv+0.5*Rsa+Rnet) -q;
e5= ABP-q*(Rla+0.5*Rsa)-Psa;
Eqnsfcn = matlabFunction([e1, e2, e3, e4, e5], 'Vars',{[Rsa, Vsa, P3, q, Psa]});
B0 = rand(1,5)*100; %initial parameters
[B,fval] = fsolve(Eqnsfcn, B0);
Bc = num2cell(B);
[Rsa, Vsa, P3, q, Psa] = Bc{:}
The fsolve function requests that you allow it more function evaluations (and probably more iterations as well). You can do that with the optimoptions (link) function.
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Star Strider 2019년 4월 16일
I am lost.
What do you want to do with ‘ABP’? If you want to change it in every iteration of fsolve, delete it from your syms list, create it as an additional parameter, add it to the argument list, and change it in a loop that evaluates ‘Eqnsfcn’.
First eliminate ‘ABP’ as a defined constant (comment it out), and chnange its name in the symbolic code to prevent later conflicts. Then, add it to the 'Vars' name-value pair as a separate argument (not one you want in the parameter vector), and then call fsolve in a loop.
Try this:
syms Rsa Vsa P3 q Psa Rsab Vsab Csa Pic Rsv Rlv Pvb Rnet ABPs Rla real
Rsab = V.Rsab;
Vsab = V.Vsab;
Csa = V.Csa;
Pic = V.Pic;
Rsv = V.Rsv;
Rlv = V.Rlv;
Pvb = V.Pvb;
Rnet = V. Rnet;
% ABP = V.ABP;
Rla = V.Rla;
e1= Rsab/(Vsa/Vsab)^2 -Rsa;
e2= Csa*(Psa-Pic) -Vsa;
e3= q*Rlv+Pvb-P3;
e4= (Psa-P3)/(Rsv+0.5*Rsa+Rnet) -q;
e5= ABPs-q*(Rla+0.5*Rsa)-Psa;
Eqnsfcn = matlabFunction([e1, e2, e3, e4, e5], 'Vars',{[Rsa, Vsa, P3, q, Psa],ABPs});
B0 = rand(1,5); %initial parameters
options = optimoptions(@fsolve, 'MaxFunctionEvaluations',150000, 'MaxIterations',15000);
ABPv = 60:0.1:180;
[Rsa, Vsa, P3, q, Psa] = deal(zeros(1, numel(ABPv))); % Preallocate
for i=1:length(ABPv)
[B,fval(i,:)] = fsolve(@(b)Eqnsfcn(b,ABPv(i)), B0, options);
Rsa(i) = B(1);
Vsa(i) = B(2);
P3(i) = B(3);
q(i) = B(4);
Psa(i) = B(5);
end
That worked when I tested it.

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