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Matlab should have give array but it gives a number. How to fix?

조회 수: 1 (최근 30일)
Ege Tunç
Ege Tunç 2019년 3월 16일
편집: Jan 2019년 3월 18일
I have a code to calculate some lambda values then uses these values with our r values to find d values. However, these values are 1x21 array but the given answer is just a number why? and how to fix this?
U=[10 9.7 9.4 9.1 8.8 8.5 8.2 7.9 7.6 7.3 7.0 6.7 6.4 6.1 5.8 5.5 5.2 4.9 4.6 4.3 4.0];
h=6.625.*10.^(-34);
m=9.109.*10.^(-31);
e=1.602.*10.^(-19);
lambda=h./sqrt(2.*m.*e.*U.*1000);
R=65.*10.^(-3);
r1i=[0.7 0.75 0.8 0.85 0.9 0.9 1.05 1.05 1.1 1.1 1.1 1.15 1.15 1.10 1.10 1.10 1.10 1.15 1.10 1.15 1.2];
r1o=[1.2 1.3 1.35 1.4 1.4 1.45 1.5 1.55 1.55 1.6 1.6 1.67 1.67 1.75 1.75 1.8 1.9 1.9 2 2.05 2.1];
r2i=[0.75 0.75 0.85 0.95 1 1 1.05 1.1 1.1 1.1 1.1 1.15 1.2 1.2 1.25 1.25 1.25 1.3 1.3 1.3 1.35];
r2o=[1.25 1.3 1.4 1.4 1.45 1.45 1.5 1.55 1.6 1.65 1.65 1.7 1.7 1.75 1.85 1.9 1.9 1.95 2 2.05 2.1];
r3i=[0.7 0.75 0.75 0.8 0.85 0.85 0.9 0.95 1 1 1 1 1.05 1.05 1.05 1.1 1.1 1.15 1.15 1.15 1.2];
r3o=[1.2 1.25 1.3 1.35 1.4 1.45 1.5 1.5 1.55 1.6 1.6 1.65 1.7 1.7 1.75 1.8 1.85 1.9 1.95 2 2.05];
d1i=(2*R.*lambda)/(10.^(-2).*r1i);
d1o=(2*R.*lambda)/(10.^(-2).*r1o);
d2i=(2*R.*lambda)/(10.^(-2).*r2i);
d2o=(2*R.*lambda)/(10.^(-2).*r2o);
d3i=(2*R.*lambda)/(10.^(-2).*r3i);
d3o=(2*R.*lambda)/(10.^(-2).*r3o);
dinner=(d1i+d2i+d3i)/3
douter=(d1o+d2o+d3o)/3

채택된 답변

Jan
Jan 2019년 3월 16일
편집: Jan 2019년 3월 18일
Use the elementwise division:
d1i=(2*R.*lambda) ./ (10.^(-2).*r1i);
% ^
You have used the elementwise operations exhaustively, even if they are not needed, because the operands are scalars only. But at the only location, where it is needed, the matrix division / is applied. I'd use:
d1i = 2 * R * lambda ./ (1e-2 * r1i);
% or even nicer:
d1i = 200 * R * lambda ./ r1i;
By the way, compare
h=6.625.*10.^(-34);
with
h = 6.625e-34;
The first is an expensive power operation, while the second is a cheap constant - and nicer. Then your code becomes:
U = [10 9.7 9.4 9.1 8.8 8.5 8.2 7.9 7.6 7.3 7.0 6.7 6.4 6.1 5.8 5.5 5.2 4.9 4.6 4.3 4.0];
h = 6.625e-34;
m = 9.109e-31;
e = 1.602e-19;
lambda = h ./ sqrt(2 * m * e * U * 1000);
R = 65e-3;
ri = [0.7 0.75 0.8 0.85 0.9 0.9 1.05 1.05 1.1 1.1 1.1 1.15 1.15 1.10 1.10 1.10 1.10 1.15 1.10 1.15 1.2; ...
0.75 0.75 0.85 0.95 1 1 1.05 1.1 1.1 1.1 1.1 1.15 1.2 1.2 1.25 1.25 1.25 1.3 1.3 1.3 1.35; ...
0.7 0.75 0.75 0.8 0.85 0.85 0.9 0.95 1 1 1 1 1.05 1.05 1.05 1.1 1.1 1.15 1.15 1.15 1.2];
ro = [1.2 1.3 1.35 1.4 1.4 1.45 1.5 1.55 1.55 1.6 1.6 1.67 1.67 1.75 1.75 1.8 1.9 1.9 2 2.05 2.1; ...
1.25 1.3 1.4 1.4 1.45 1.45 1.5 1.55 1.6 1.65 1.65 1.7 1.7 1.75 1.85 1.9 1.9 1.95 2 2.05 2.1; ...
1.2 1.25 1.3 1.35 1.4 1.45 1.5 1.5 1.55 1.6 1.6 1.65 1.7 1.7 1.75 1.8 1.85 1.9 1.95 2 2.05];
di = 200 * R * lambda ./ ri; % Auto-expand, >= R2016b
do = 200 * R * lambda ./ ro; % Auto-expand, >= R2016b
dinner = mean(di, 1)
douter = mean(do, 1)
Less chances for typos.

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