How would I make my for loop more accurate.

a = 0;
b = 1;
c = 0;
d = 1;

for k = 1:700
    c = a + b;
    a = b;
    b = c;
    d = [d c];
end

format long
d(700)          %>>> 8.747081495575278e+145   
fibonacci(700)  %>>> 8.747081495575285e+145

I believe the function fibonacci(n) has the correct number.

How does the function fibonacci have a more accurate number?

Answer 1

[Walter Roberson]

fibonnaci() is a function in the Symbolic Toolbox. It calculates the numbers as indefinite precision software integers, and then converts the result to double.