I'm trying to make a Simpsons Rule Function Myself
조회 수: 1 (최근 30일)
이전 댓글 표시
I've had a few attempts at this question and have developed my answer further each time. If people wouldn't mind giving feedback or correcting my code that'd be great.
This is the question:
![Simpsons Rule Question Only.JPG](https://www.mathworks.com/matlabcentral/answers/uploaded_files/198970/Simpsons%20Rule%20Question%20Only.jpeg)
and the code I have written to answer this is, there is more to th question but this is just my code for the first bit:
function [y] =MPR_Asgn4_Q4a_26024405(f,a,b,n)
h=(b-a)/n;
x=zeros(1,n+1);
x(1)=a;
x(n+1)=b;
s1=0;
s2=0;
s3=0;
for k = 2:n
x(k)=a+h*(1i-1);
end
for k=1:n/2
s1= s1 + f(x(2*1i-1));
end
for k=1:n/2
s2=s2+f(x(2*1i));
end
for k= 1:n/2
s3 = s3 +f(x(2*1i+1));
end
y = (h/3)*(s1+(4*s2)+s3);
disp(y);
end
댓글 수: 2
Omer Yasin Birey
2018년 12월 14일
Hi Jack,
I tried to understand your code and the formula together. However, firstly I believe your "i" usages are quite wrong. If you put "i" or "j" without multiplication sign (*) that gives complexity to the number. However, if Im not wrong there is no calculations in complex domain here. Secondly, you are using loops without using the loop indexes maybe you meant "k" instead of "i"?
채택된 답변
Omer Yasin Birey
2018년 12월 14일
편집: Omer Yasin Birey
2018년 12월 14일
Hi Jack,
I fixed your code as much as I can. You can use the code below:
function [y] =MPR_Asgn4_Q4a_26024405(f,a,b,n)
x = linspace(a,b,n);
x(1)=a;
x(n+1)=b;
h=(b-a)/n;
s1=0;
s2=0;
s3=0;
%First if statements is to check if f is an anonymous function
%or an array.
if length(f) > 1%array state
%if it is a array your sub intervals will be the length of array
%So you have to update it.
n = length(f)-1;
h=(b-a)/n;
for k=3:2:length(f)-2
s1= s1 + 2*f(k);
end
for k=2:2:length(f)
s2=s2+f(k);
end
s3 = f(length(f));
y = (h/3)*(f(1)+(2*s1+(4*s2)+s3));
else%anonymous function state
for k=3:2:length(f)-2
s1= s1 + 2*f(x(k));
end
for k=3:2:length(f)
s2=s2+f(x(k));
end
s3 = f(length(f));
y = (h/3)*(f(x(1))+(2*s1+(4*s2)+s3));
end
disp(y);
end
댓글 수: 0
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!