Hi i'm trying to crate a table colums of table will be col1 col2 col3 col4 and col5. I have to store all iteration steps in a matrix. How can i do that?

clear;

clc;

syms m ;

h=6.626e-34;

k=1.3807*10^-3;

C2=14388;

C0=2.998e8;

C1=2*pi*h*C0^2;

for nlamdaT=1000:100:50000

eta=C2/nlamdaT;

fun=(6+(6*(eta*m))+(3*((m*eta).^2))+(((m*eta)^3)))/(exp(m*eta)*(m^4));

S=symsum(fun,m,1,inf);

f=(15/pi^4)*S;

% make the columns of table

col1=nlamdaT';

col2=(1/(nlamdaT))*10.^4;

col3=10^24*C1./((nlamdaT).^5.*(exp((C2./nlamdaT))-1));

col4=10^20*C1./((nlamdaT).^3.*(exp((C2./nlamdaT))-1));

col5=double(f);

nlamdaT=nlamdaT+10;

% create the table

T=table(col1,col2,col3,col4,col5)

end

Answer 1

[madhan ravi]

clear; clc; syms m ;
h=6.626e-34; 
k=1.3807*10^-3; 
C2=14388; 
C0=2.998e8;
C1=2*pi*h*C0^2;
ctr=1;
T=table;
for nlamdaT=1000:100:50000
    eta=C2/nlamdaT; 
    fun=(6+(6*(eta*m))+(3*((m*eta).^2))+(((m*eta)^3)))/(exp(m*eta)*(m^4)); 
    S=symsum(fun,m,1,inf); f=(15/pi^4)*S; % make the columns of table 
    col1(ctr)=nlamdaT'; 
    col2(ctr)=(1/(nlamdaT))*10.^4; 
    col3(ctr)=10^24*C1./((nlamdaT).^5.*(exp((C2./nlamdaT))-1));
    col4(ctr)=10^20*C1./((nlamdaT).^3.*(exp((C2./nlamdaT))-1)); 
    col5(ctr)=double(f);
%     T=nlamdaT+10; % NO NEEDED
    x=table(col1(ctr),col2(ctr),col3(ctr),col4(ctr),col5(ctr));
    T = [T; x];
    ctr = ctr+1;
end
T

[madhan ravi]

Solved it using counter!

[Zuy]

Thank you so much!

[madhan ravi]

Anytime :)

[Peter Perkins]

If I am reading this code correctly, take these two lines

x=table(col1(ctr),col2(ctr),col3(ctr),col4(ctr),col5(ctr));
T = [T; x];

Out of the loop, and put this line

T = table(col1,col2,col3,col4,col5);

after the loop.

[madhan ravi]

Thank you! @Perkins its simple :)