Round towards specific values in an array
조회 수: 52 (최근 30일)
이전 댓글 표시
Hi, when I have 2 vectors, one vector has a larger length than the other. But they both have values that are approximately the same. Now I want to round and locate each element of the large vector in the short vector. So, for example:
A = [2000 1999 1998 1996 1993 .... 0] (dim=1 x a)
B = [2000 1995 1990 1985 1980 .... 0] (dim=1 x b)
I would now like to see that for example {2000 1999 1998} of A are rounded to {2000} in B and {1996 1993} in A to {1995} in B so that I can find the index of an element in B that corresponds to one (or more) rounded values in A.
I can imagine that you can do this with some kind of for-loop, but preferably I do not use that since it will become a nested loop and will cost a lot of computation time.
THanks a lot
댓글 수: 0
답변 (4개)
Tom Gaudette
2011년 3월 29일
% This solutions currently does it with loops just to get a picture of the problem.
A = [2000 1999 1998 1996 1993 1990];
B = [2000 1995 1990 1985 1980];
for idx1=1:length(A);
for idx2=1:length(B);
C(idx2,idx1)=A(idx1)-B(idx2);
end;
end
% Now find the index of the min values
[v,i]=min(abs(C));
% 'i' now contants the list of locations in B that corespond to the nearest
% A value
B(i)
Teja Muppirala
2011년 3월 29일
This is one possible solution. If your vectors are very long though, this might be inefficient because it temporarily makes a big matrix to calculate all the differences.
A = -5 + 35*rand(1,100);
B = 0:5:25;
[~,I] = min(abs(bsxfun(@minus,A,B')));
Anew = B(I);
[A; Anew]
댓글 수: 0
Steven Lord
2022년 8월 8일
A = [2000 1999 1998 1996 1993].';
B = [2000 1995 1990 1985 1980].';
Assuming all the elements of B are unique, interpolate to 'nearest'.
C = interp1(B, B, A, 'nearest');
result = table(A, C, 'VariableNames', ["Original data", "Rounded data"])
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Logical에 대해 자세히 알아보기
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!