How many times each element of an array have the 1 value after n times assigned different logical values?
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I have n same size matrices containing different logical values such as A1, A2, A3 matrices. It also can be considered that a matrix_A was assigned n times with different logical values 1 and 0. Please help to point out how to count the number of times each elements of this A matrix having 1 value. Any suggestion would be much appreciated!
A1 = 1 0 0 1 0 1 0
0 1 0 1 0 0 0
0 1 1 0 0 1 0
0 1 1 0 1 0 1
A2 = 1 0 0 0 0 1 0
0 1 0 0 0 0 0
0 1 1 1 0 1 0
0 1 1 1 1 0 1
A3 = 0 0 0 0 0 1 1
0 1 1 1 1 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 1
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채택된 답변
Stephen23
2018년 9월 21일
편집: Stephen23
2018년 9월 21일
Simple: use one 3D array:
A = cat(3,...
[1 0 0 1 0 1 0
0 1 0 1 0 0 0
0 1 1 0 0 1 0
0 1 1 0 1 0 1],...
[1 0 0 0 0 1 0
0 1 0 0 0 0 0
0 1 1 1 0 1 0
0 1 1 1 1 0 1],...
[0 0 0 0 0 1 1
0 1 1 1 1 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 1]);
And then:
>> sum(A,3)
ans =
2 0 0 1 0 3 1
0 3 1 2 1 0 0
0 2 2 1 0 2 0
0 2 2 1 2 0 3
Note: if your arrays are in one cell array C then you can easily conver this into a 3D array:
A = cat(3,C{:});
If you have lots of separate variables, then you need to fix your code design.
추가 답변 (1개)
Fangjun Jiang
2018년 9월 21일
Constructing your data as 3d matrix will make it easy.
A(1,:,:) =[ 1 0 0 1 0 1 0
0 1 0 1 0 0 0
0 1 1 0 0 1 0
0 1 1 0 1 0 1];
A(2,:,:) = [1 0 0 0 0 1 0
0 1 0 0 0 0 0
0 1 1 1 0 1 0
0 1 1 1 1 0 1];
A(3,:,:) = [0 0 0 0 0 1 1
0 1 1 1 1 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 1];
m=4;
n=5;
sum(A(:,m,n))
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