# How to do matching in table format?

조회 수: 20(최근 30일)
SC 2018년 8월 17일
답변: Peter Perkins 2018년 8월 24일
Hi,
I have some data, putting in a matrix A:-
Col1 = [1;4;0];
Col2 = [2;5;2];
Col3 = [3;6;4];
A = [Col1,Col2,Col3]
I want to extract the rows where column 2 have the value 2 (i.e. c), and also have another output with those values being updated from 2 to 200 (i.e. d).
b=(A(:,2)==2);
c=A(b,:)
d=A;
d(b,2)=200
However, now the data I obtained is a table, instead of a matrix:-
A2 = table(Col1,Col2,Col3)
I tried to use A2 to replace A in the above codes and try to obtain c and d, but I failed.
How can I obtain c and d? Many thanks!
##### 댓글 수: 1표시숨기기 없음
dpb 2018년 8월 18일
If the operations on the data are more convenient as array rather than as separate variables, then create the table variable as an array instead --
A2=table(A);
If there are specific reasons for keeping separate columns because most is column/variable related but there's the occasional array operation, you can retrieve the desired columns as array--
A2=table(Col1,Col2,Col3);
a=A{:,1:3};
and a is the array equivalent to A above to operate on and then put result back into the table.

댓글을 달려면 로그인하십시오.

### 채택된 답변

Peter Perkins 2018년 8월 24일
b = (A2.col2 == 2); % or A2{:,2) == 2
c = A(b,:) % leave this as a table
d = A2;
d.Col2(b) = 200; % or d{b,2} = 200
There's quite a lot of documentation about table subscripting that will explain all this.

댓글을 달려면 로그인하십시오.

### 범주

Find more on Tables in Help Center and File Exchange

R2016a

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!