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How do I access a field on a struct which is not always in the same level?

조회 수: 3 (최근 30일)
Ana
Ana 2018년 6월 27일
편집: Ana 2018년 6월 27일
Hello,
I have a problem in generalizing a code for different structure contents. The problem is that I need to access a field (let's say subfield1) which is not always in the same level of the structure.
var1.subfield1 = 1;
var2.field1.subfield1 = 3;
I would like to be able to define a variable, fieldname, that would be empty for var1 and 'field1' for var2, so that:
var1.(fieldname).subfield1
var2.(fieldname).subfield1
would work and give me the value of that field. However if I set:
fieldname=''
and try to execute the first line, this gives an error:
Reference to non-existent field ''.
I have also tried using the getfield function, with no success.
Is there any solution for this, or should the structures have the same fields from the beginning to be able to do this?
Thank you very much in advance,
Ana Gómez
  댓글 수: 3
Ana
Ana 2018년 6월 27일
Yes, that would be one option.
The problem is that I am using this quite often in the code so it would be more recommendable if I could avoid filling it of "if" statements if there is the possibility.
Thanks in any case for the suggestion.
KSSV
KSSV 2018년 6월 27일
Why don't you create some dummy filedname.....this dummy filedname will be already known to you....
var1.dummy.subfield1 = 1;
var2.field1.subfield1 = 3;

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채택된 답변

Jan
Jan 2018년 6월 27일
편집: Jan 2018년 6월 27일
Create a function which checks the existence of the subfield:
function Data = getSubField(S, F1, F2)
if isfield(S, F2)
Data = S.(F2);
elseif isfield(S, F1)
Data = S.(F1).(F2);
else
Data = [];
end
Now call this like:
var1.subfield1 = 1;
var2.field1.subfield1 = 3;
Data1 = getSubField(var1, 'field1', 'subfield1');
Data2 = getSubField(var2, 'field1', 'subfield1');
If run-time matters, this might be faster - or slower (try it by your own):
function Data = getSubField(S, F1, F2)
try
Data = S.(F2);
catch
try
Data = S.(F1).(F2);
catch
Data = [];
end
end

추가 답변 (1개)

Stephen23
Stephen23 2018년 6월 27일
편집: Stephen23 2018년 6월 27일
This is easy with getfield, you just need to define a cell array of the required fieldnames:
>> var1.subfield1 = 1;
>> var2.field1.subfield1 = 3;
>> c1 = {'subfield1'};
>> c2 = {'field1','subfield1'};
>> getfield(var1,c1{:})
ans = 1
>> getfield(var2,c2{:})
ans = 3
  댓글 수: 1
Ana
Ana 2018년 6월 27일
Thanks for the answer! In the use I was making in my code, having a function was more appropriate, so I finally used Jan's answer, but this is also very useful for some other problems I may face in the future.

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