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problems with a trascendental equation

조회 수: 1 (최근 30일)
alburary daniel
alburary daniel 2018년 6월 10일
댓글: Walter Roberson 2018년 7월 27일
I tried all day to run my program
syms R t;
eqn = R*tan(10022.99039*R)-(6.97964*10^-3*sqrt(t))/R==0 ;
m = linspace(10,20,1) ;
sol = zeros(size(t)) ;
for i =1 :length(m)
eqn = subs(eqn,t,m(i)) ;
sol(i) = double(solve(eqn,R)) ;
end
plot(m,sol)
but matlab give me the issues
Error using mupadmex
Internal error with symbolic engine. Quit and restart MATLAB.
Error in sym>cell2ref (line 1303)
S = mupadmex(y);
Error in sym>tomupad (line 1241)
S = cell2ref(numeric2cellstr(x));
Error in sym (line 215)
S.s = tomupad(x);
Error in syms (line 197)
toDefine = sym(zeros(1, 0));
Error in SOLUCION1 (line 3)
syms R t;
any suggestion ?
  댓글 수: 1
Walter Roberson
Walter Roberson 2018년 7월 27일
Please do not close questions that have an answer.

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채택된 답변

John D'Errico
John D'Errico 2018년 6월 10일
편집: John D'Errico 2018년 6월 10일
You probably need to start with the basic tutorials to learn MATLAB. For example, you do this:
m = linspace(10,20,1)
m =
20
Then you run a loop for the length of m. m is a scalar. You have not created a vector at all.
You do other strange things, like this:
sol = zeros(size(t)) ;
But t is a scalar symbolic variable. Why do you think you need to preallocate sol as a scalar variable?
Next, you try to use solve on eqn.
pretty(vpa(eqn,5))
0.0069796 sqrt(t)
R tan(10023.0 R) - ----------------- == 0.0
R
Here, t takes on ONLY the value 20, so lets look at eqn after the subs.
pretty(vpa(subs(eqn,t,20),5))
0.031214
R tan(10023.0 R) - -------- == 0.0
R
Now, admittedly, this will be poorly scaled, because you are multiplying R by 10023, and THEN taking the tangent. And there will be infinitely many solutions.
So lets look at your problem. PLOT IT.
fun = @(R,t) R.*tan(10022.990390000000843429006636143*R) - (0.006979639999999999629143321300262*sqrt(t))./R
fun =
function_handle with value:
@(R,t)R.*tan(10022.990390000000843429006636143*R)-(0.006979639999999999629143321300262*sqrt(t))./R
ezplot(@(R) fun(R,20),[.001 .075])
refline(0,0)
Hmm. Lets zoom in way tighter. Even in that area where there appear to be no solutions...
ezplot(@(R) fun(R,20),[.038 .045])
Do you see each of those spikes that zooms up to infinity on the y axis? Each of them crosses zero. So now lets just pick some small region:
ezplot(@(R) fun(R,20),[.041 .042])
So there are infinitely many solutions. Just no way to write them all down. It is not like they will be equally spaced, either. Sorry, but the reason the solve tools crapped out is your problem has essentially no solution, in the sense that there are infinitely many solutions, but no way to represent them.
So, can you solve this? NO. Yes, you can use fzero, and find any specific root. Or, for that matter, you can use vpasolve, and find ONE root. But you need to think about what you are doing. You need to plot the stuff you are trying to solve. Don't just throw stuff at a solver and expect it to magically return all of infinitely many solutions at you. Apply common sense.

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