How to replace zeros in a matrix by the elements of an array?
조회 수: 2 (최근 30일)
이전 댓글 표시
Hi everybody! I have a matrix (A) that contains zeros but it may contain also ones.
R=1:8; A=[1 0 0 0;
0 0 0 0;
1 0 1 1]
How to replace all the ones by zeros and all the zeros by elements of an array (R) going column-wise so that the resulting matrix (B) would look like:
B=[0 2 5 7;
1 3 6 8;
0 4 0 0]
댓글 수: 2
채택된 답변
Thomas
2012년 6월 6일
You are on the right track, though it can be done in much simpler way but since you are a beginner this will suffice..
use
Your input matrix was zeros, just add a count for R values
Editing your code:
A=[1 0 0 0;
0 0 0 0;
1 0 1 1]
D=3;
N=4;
% A=zeros(D,N);
equations=sum(A(:)==0);
R=1:equations;
count=1;
for j=1:N
for i=1:D
if A(i,j)==1
A(i,j)=0;
else
ID(i,j)=R(count);
count=count+1;
end
end
end
ID
댓글 수: 3
추가 답변 (1개)
Image Analyst
2012년 6월 6일
R=1:8;
A=[1 0 0 0;
0 0 0 0;
1 0 1 1]
linearIndices = A == 0
B = A; % Make a copy.
B(A==1) = 0
B(linearIndices) = R;
This is a vectorized way of doing it rather than your for loop method.
참고 항목
카테고리
Help Center 및 File Exchange에서 Get Started with MATLAB에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!