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dsolve problem

조회 수: 2 (최근 30일)
Daniel
Daniel 2012년 5월 31일
Hello, I would like to use a function f in a differential equation for example f=x but get a crazy result.
syms x y f
f=x
y=dsolve('D2x=-f','x(0)=1','Dx(0)=0')
How can I put into dsolve a function f defined outside of dsolve?

채택된 답변

Teja Muppirala
Teja Muppirala 2012년 6월 1일
One way would be to convert f to a string:
syms x y f
f=x
y=dsolve(['D2x=-' char(f)],'x(0)=1','Dx(0)=0')
  댓글 수: 1
Daniel
Daniel 2012년 6월 1일
Thank you Teja!

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추가 답변 (1개)

Walter Roberson
Walter Roberson 2012년 5월 31일
You could try
syms x y f
f=x
eqn1 = subs(sym('D2x=-f'), 'f', f);
y = dsolve(eqn1, 'x(0)=1','Dx(0)=0')
  댓글 수: 3
Walter Roberson
Walter Roberson 2012년 5월 31일
Ah, I guess it doesn't analyze syms for occurrences of D. Ummm, I will have to make up a variable for x to be related to:
If I read the documentation right,
syms x(t) f(t) t
f = x(t); %or maybe f = x;
D2x = diff(x,2);
Dx = diff(x);
dsolve( D2x == -f, x(0) == 1, Dx(0) == 0 )
Anyhow, the root of the problem is that, as usual, when you have a quoted string like 'D2x=-f', MuPAD does not have access to the value of any variable such as f that was declared at the MATLAB level. subs() is the mechanism to "import" MATLAB-level values to the MuPAD level. It looks like dsolve() interprets symbolic variables differently than it interprets strings so the more obvious subs() does not work. char() around the subs() might perhaps have worked.
Daniel
Daniel 2012년 6월 1일
Thanks for trying.
Teja's code works:
syms x y f
f=x
y=dsolve(['D2x=-' char(f)],'x(0)=1','Dx(0)=0')

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