How do I add a value to an adjacent element without for loop

    % x = zeros(1,7)
      x(1) = 3
      x(2) = 4
      lengthofx = length(x)
      x(3:end) = x(2:end-1)+1

I was wondering how to add a value to a next element without for loop? I'm given x(1) = 3, and x(2) is 4, and

I'm trying to add one to the next element so add 1 to element 3, then add 1 to element 3, and so on but this part

doesn't work: x(2:end) = x(1:end-1)+1.

It adds one to element 3 which becomes 5, but then when it reaches to element 4 it just adds 1 to it, so the element value is one instead of 6

Answer 1

[Birdman]

Try this:

x=zeros(1,7);
x(1)=3;
x(2)=4;
x(find(x==0,1,'first'):end)=x(find(x~=0,1,'last'))+1:x(find(x~=0,1,'last'))+sum(x==0)

[jake stan]

thanksssss

[jake stan]

x(find(x==0,1,'first'):end)=x(find(x~=0,1,'last'))+1:x(find(x~=0,1,'last'))+sum(x==0)

What does the semicolon do between "+1:x"

[Birdman]

That semicolon just vectorizes the right hand of the code.

[jake stan]

Oh it doesn't work when I want to change the addition value, so instead of adding one it adds like 6 or any number

[Birdman]

Ok, try this: By changing N, you will add any value you want,

x=zeros(1,9);
x(1)=3;
x(2)=4;
N=6
x(find(x==0,1,'first'):end)=(x(find(x==0,1,'first'))+1:N:N*(x(find(x==0,1,'first'))+sum(x==0)))+x(find(x~=0,1,'last'))-1+N