# Why boxplot grouping variable plotted out of order?

조회 수: 23(최근 30일)
Daniel Bridges 2018년 2월 28일
댓글: Walter Roberson 2018년 10월 19일
Why is the grouping variable not plotted in the order I've listed it in my code? How do I make it plot sequentially? Please compare the figure with its code. group = cell(1,2);
doseloop = 192;
for loop = 1:height(newvoldata{doseloop})
if strcmpi('blurred',newvoldata{doseloop}.DistributionType(loop))
switch newvoldata{doseloop}.StudyID(loop)
case {1,2,3,4,5,6,7,8,9,10,13,36} %12
group{2} = [group{2}; 'Grade 0'];
case {14,15,19,20,21,22,23,29,30,31,34,37,38,39} % 14
group{2} = [group{2}; 'Grade 1'];
case {11,12,16,17,18,25,26,27,28,32,33,35,40} % 13
group{2} = [group{2}; 'Grade 2'];
case 24 % 1
group{2} = [group{2}; 'Grade 3'];
otherwise
error('Our code didn''t work as planned.')
end
group{1} = [group{1}; newvoldata{doseloop}.Dose(loop)];
end
end
figure
boxplot(newvoldata{doseloop}.Volume(strcmpi('blurred',newvoldata{doseloop}.DistributionType)),group)
title([organofinterest,' Blurred DVH Comparison for 40 Pt Given GU Toxicity'])
ylabel('Percent Volumes receiving given dose, %')

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### 채택된 답변

Walter Roberson 2018년 2월 28일
1 to 10 are Grade 0. 11 is Grade 2. If the labels are to be displayed according to numeric order of the source then that is going to result in Grade 0 then Grade 2 appearing, exactly as happens.
boxplot has no knowledge of how the data was computed. If you had rearranged the case order or scrambled the numeric order of the numbers within the case then the computed data would be the same and the display would be the same.
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Walter Roberson 2018년 10월 19일
Use the syntax
B = categorical(A,valueset,catnames)
The sorting will be by the value you associate in valueset, but the names will be what you give in catnames.

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