I have lots of wave file. How do I read each one of them using sprintf command?
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The wave file are like.The first digit- speaker id, second digit-utterence id
- 00
- 01
- 02
- 03
- 04
- .
- .
- .
- 59
I tried using
for m=0:5
for y=0:9
file=sprintf('%s%d%d','E:\0 (1)\0\',m,y);
[s,fs]=wavread(file);
end
end
But this gives error. Alternatively I tried
mypath = 'E:\\0 (1)\\0\\';
filename = sprintf([mypath '%s%d.wav'],m,y);
[s,fs] = audioread(filename);
But it gave error as : Function is not defined for sparse inputs.
Please help me.
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Walter Roberson
2018년 1월 28일
mypath = fullfile('E:', '0 (1)', '0');
for m = 0 : 5
for y = 0 : 9
filename = fullfile(mypath, sprintf('%d%d.wav', m, y));
[s, fs] = audioread(filename);
...
end
end
Or in your situation you could use a single loop:
mypath = fullfile('E:', '0 (1)', '0');
for idx = 0 : 59
filename = fullfile(mypath, sprintf('%02d.wav', idx));
[s, fs] = audioread(filename);
...
end
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Image Analyst
2018년 1월 28일
Your first code:
for m=0:5
for y=0:9
file=sprintf('%s%d%d','E:\0 (1)\0\',m,y);
[s,fs]=wavread(file);
end
end
gets the file (perhaps) but doesn't do anything with the s and fs it retrieved.
There are ways you could make your code more robust, for example by checking in advance if the file exists before calling wavread(), and by updating to the new function audioread(), etc.
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