Eigen value eigen vectors in matlab
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I want to solve this question.I'm going to atteched my code but I don't know this code is true.
if true
clc;
clear all;
A=[4 -5;-2 1];
Eig=eig(A)
F=poly(A)
[V,D]=eig(A)
V1=V(:,1)
V11=V1/V(1,1)
end
댓글 수: 1
Walter Roberson
2018년 1월 21일
What are you doing with the Eig and F values you calculate?
I do not see any initial value problem in the question presented: it gives the initial value. Initial value problems require that information about the original condition is missing and needs to be calculated, which is not the case here.
채택된 답변
Birdman
2018년 1월 21일
Your approach is nice, but not enough of course. First, you need to construct a differential equation for your second question. Third question comes with the second one. The answer for your first question is included in this line:
[V,D]=eig(A)
Full solution may look like as follows:
%%1st
A=[4 -5;-2 1];
[V,D]=eig(A)
%%2nd
syms x1(t) x2(t)
x0=[2.9;2.6];
eq1=diff(x1,t)==A(1,:)*[x1(t);x2(t)];
eq2=diff(x2,t)==A(2,:)*[x1(t);x2(t)];
solx=dsolve([eq1 eq2],[x1(0)==2.9 x2(0)==2.6]);
x1=solx.x1
x2=solx.x2
%%3rd
t=subs(t,0:0.1:1);
x1=subs(x1,t);
x2=subs(x2,t);
plot(t,x1,'o',t,x2,'-*')
댓글 수: 2
추가 답변 (2개)
johnson wul
2019년 7월 23일
Nice that. is this formular for eigenvector:
plot(t,x1,'o',t,x2,..,t,x10, '-*')
have been used to for square matrix 10*10 for example if some one want to plot differents eigenvectors?
And how to plot in 3 dimensions the previous eigenvectors? just a step
댓글 수: 0
mercy charles
2022년 2월 19일
%%1st
A=[4 -5;-2 1];
[V,D]=eig(A)
%%2nd
syms x1(t) x2(t)
x0=[2.9;2.6];
eq1=diff(x1,t)==A(1,:)*[x1(t);x2(t)];
eq2=diff(x2,t)==A(2,:)*[x1(t);x2(t)];
solx=dsolve([eq1 eq2],[x1(0)==2.9 x2(0)==2.6]);
x1=solx.x1
x2=solx.x2
%%3rd
t=subs(t,0:0.1:1);
x1=subs(x1,t);
x2=subs(x2,t);
plot(t,x1,'o',t,x2,'-*')
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