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Get row no where comparison gives 1

조회 수: 2 (최근 30일)
Tha saliem
Tha saliem 2018년 1월 2일
댓글: Tha saliem 2018년 1월 3일
Hey i have a cell array:
A={[4x9 cell],[3x9 cell],[2x9 cell]}
A{1,1}= [1,-0.03,0.1,1.3,0,0.23,1,0,0.2; 1,0.6,0.14,2,0,0.6,0.6,0,0.6; 1,-0.15,0,1.4,0,0.35,1,0,0.38; 2,-0.2,0.18,3,0,0.4,0,0,0.4]; similarly values for A{1,2} and A{1,3}
I have compared each row of A{1,1} with every other row in A{1,1} using
A(1:end-1,:)<A(2:end,:)
Now what I want to find is that how can I get the row no's which are being compared at a particular time. For example if row 1 and row 2 are being compared how can I get 1 and 2 in result.
I want to store all elements where result of comparison is 1. for example if row 1 and row 4 gives 1 in result then I want to store the row no where the result is 1 ( like 1 and 4 in this example).
please help.

채택된 답변

Walter Roberson
Walter Roberson 2018년 1월 2일
repmat((1:size(A,1)-1).', 1, size(A,2)) .* (A(1:end-1,:)<A(2:end,:))
which would give you
0 1 1 1 0 1 0 0 1
0 0 0 0 0 0 2 0 0
3 0 3 3 0 3 0 0 3
for whatever good that would do you.
  댓글 수: 10
Walter Roberson
Walter Roberson 2018년 1월 2일
The output of find() is the row number minus 1, so just add 1.
Tha saliem
Tha saliem 2018년 1월 3일
Thank You so much for helping.

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