Images read and comparing with every other images in database

I have folder name data and under this folder 40 folders (named A1 to A40) and each one have 10 gray images so total 400 images. I would like to compare each image with other 399 images .I have comparision code.I tried but could not come up with an efficient code. So, could someone please suggest me an idea or code at least how to read those images.

Answer 1

[KALYAN ACHARJYA]

   % Please save all images name in symetric manner before doing the operation 
   % names for example im1,im2,im3...
   % Pls ensure both folder images having equal numbers of images
   %Save the folder of images in the current directory
   path_directory='optha_original'; % 'Folder name'
   % Pls note the format of images,change it as required
   original_files=dir([path_directory '/*.jpg']); 
   l=1;
   for k=1:length(original_files)
      filename=[path_directory '/' original_files(k).name];
      image_orginal=imread(filename);
      % Image read is done
      %%Following code for Image Call
      images_call='images1'; % 'Folder name'
      call_files=dir([images_call '/*.gif']); % Alert: Image format
      filename=[images_call '/' call_files(l).name];
      l=l+1; % This increment for next call images
      call_image=imread(filename);
     % Now you have two images image_orinal>original image
     % and call_image> call image for compare
     % Next do your operation and finding
  end

Answer 2

[KSSV]

S = dir ;  % get folders in the directory 

for i = 3:length(S)    % loop for each folder 
    foldername = S(i).name ;
    if S(i).isdir
       files = dir('*.png') ;   % your image extension 
       N = length(files) ;  % total images 
       for j = 1:N  % loop for each image
           imagename = files(j).name ;
           I = imread(imagename) ;
       end
    end
end