필터 지우기
필터 지우기

Can you help me ?

조회 수: 2 (최근 30일)
SULE SAHIN
SULE SAHIN 2017년 11월 7일
댓글: Walter Roberson 2019년 1월 4일
Write a function called year2016 that returns a row-vector of struct-s whose elements correspond to the days of a month in 2016 as specified by the input argument. If the input is not an integer between 1 and 12, the function returns the empty array. Each struct should contain three fields with these (exact) field names: “month”, “date”, and “day” (all lower case).
  • The month field must contain a string with the name of the month (first letter capitalized).
  • The date field must contain a scalar specifying the day of the month.
  • The day field must contain the three-letter abbreviation of the day chosen from this list: 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'.
For example, here is a call of the function followed by a command that shows the seventh element of the struct array that is returned by the function:
>> m = year2016(2);
>> m(7)
ans =
month: 'February'
date: 7
day: 'Sun'
My code is here;
function x = year2016(m)
year2016.month = {'January';'February';'March';'April';'May';'June';'July';'August';'September';'October';'November';'December'};
TypeList = {'Mon','Tue','Wed','Thu','Fri','Sat','Sun'};
for k = 1:numel(TypeList)
x = TypeList{k};
if month >0 && month<=12
return;
end
end
x = 'NONE';
I know that it has many error but I haven't associate month , day and date. Please help me?
  댓글 수: 3
Walter Roberson
Walter Roberson 2018년 4월 27일
Please do not close questions that have an answer.

댓글을 달려면 로그인하십시오.

답변 (2개)

shah109
shah109 2017년 12월 24일
편집: Walter Roberson 2017년 12월 25일
% I modified this function from stephen cobeldick post
function out = year2016(m)
if ~isscalar(m) || m <1 || m~=fix(m)
out = [];
else
VN = datenum([2016,m,1]):datenum([2016,m+1,1])-1;
DN = 1+mod(VN-3,7);
MC = {'January';'February';'March';'April';'May';'June';'July';'August';'September';'October';'November';'December'};
DC = {'Mon','Tue','Wed','Thu','Fri','Sat','Sun'};
out = struct('day',DC(DN),'date',num2cell(1:numel(VN)));
[out(:).month] = deal(MC{m});
end
  댓글 수: 2
Emma Sellers
Emma Sellers 2019년 1월 4일
I have tried using a code similar to this and I get an error when the code runs
m = [1 2 ]
what needs to be added?
I tried adding sizeof(m)>1 to line three and that did not help.
Walter Roberson
Walter Roberson 2019년 1월 4일
that should be caught by the isscalar test.

댓글을 달려면 로그인하십시오.


Ugur Ulas
Ugur Ulas 2018년 1월 10일
편집: Ugur Ulas 2018년 1월 10일
Hello, it s another solution:
function m = year2016(A,B)
day_no = datenum(2016,A,1)-datenum(2016,0,1);
day_mod = mod((B+day_no+4),7);
if day_mod == 0
day_mod = 7
end
month = {'January' 'February' 'March' 'April' 'May' 'June' 'July' 'August' 'September' 'October' 'December' 'November'};
day = {'Mon' 'Tue' 'Wed' 'Thu' 'Fri' 'Sat' 'Sun'};
if 0>A || 12<A || 0>B || (datenum(2016,A+1,1)-datenum(2016,A,1))<B
m = struct([])
else
a = month{A};
b = day{day_mod};
m = struct('month',a,'date', B ,'day',b);
end
end

카테고리

Help CenterFile Exchange에서 Dates and Time에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by