Hello,
I have a cell with string elements and I am trying to check if they exist as variables:
A={'B0','B01','B04'}
for i=1:3
if exist(A(i,1),'var')==1
...
This does not work so what do I do? Thx!

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Walter Roberson
Walter Roberson 2012년 4월 12일

1 개 추천

if exist(A{i,1},'var')
Notice the {} instead of ()

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osminbas
osminbas 2012년 4월 12일
You rock, Walter!
It doesn't work for me! Here's the code:
>> h = {1,2;3,4};
>> exist('h','var')
ans =
1
>> exist('h{1}','var')
ans =
0
>> exist('h{1,1}','var')
ans =
0
Am I making any mistake? If not, is there any other way to check existence of different elements in a cell array?
Thanks
Matt J
Matt J 2012년 12월 7일
편집: Matt J 2012년 12월 7일
You have several errors. First, notice that Walter doesn't enclose the first argument to exist() in quotes. Secondly, your h{i,j} data are not relevant examples because they are not strings.

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추가 답변 (1개)

RNTL
RNTL 2012년 4월 12일

1 개 추천

ismember(A,who)

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osminbas
osminbas 2012년 4월 12일
Actually, I am really trying to use exist and check the elements one by one in a loop so ismember(A,who) would not work for me.
Jan
Jan 2012년 12월 7일
@osminbas: Please take the time to think twice. This method would help to avoid the loop or at least compare all elements of the cell string h in a very compact form.

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