Drawing hyperbola using patch function.

I have to draw points in matlab which show trade-off (i.e, inversely relationship) for this reason I have to draw the hyperbola-like shape. I used the code shown below to draw points by using patch file now I need to hyperbola by using patch function.

% line([.1 .1 6 6 .1 .1],[.81 2.735  164 48.6 .81 2.735],'Marker','*','Color','k','LineStyle','-');
% line([4 4 6 6],[57 95 57 95],'Color','b','LineStyle','-');
patch([1.5 13.84 1.5],[13.8 1 288],'c','LineStyle','-')
%%%%%%%%%%%%%%%%P2 %%%%%%%%%%%%%%%%%%%%
x = [0.76 0.69];
y = [0.78 0.83];
annotation('textarrow',x,y,'String','P_{2}(29,405)')
% % %%%%%%%%%%%%%%%%%%%%P1 %%%%%%%%%%%%%%%
x = [0.65 0.60];
y = [0.47 0.55];
annotation('textarrow',x,y,'String','P_{1}(24,288)')
% % %%%%%%%%%%%%%P3%%%%%%%%%%%%
x = [0.76 0.69];
y = [0.60 0.65];
annotation('textarrow',x,y,'String','P_{3}(29,334)')

[Walter Roberson]

http://www.mathworks.co.uk/matlabcentral/answers/43073-a-guide-to-tags

[Walter Roberson]

Why does it need to be patch()? Do you need to draw a line that changes color? Do you need to texturemap on top of it? Do you need to make semi-transparent lines?

Have you considered using fill() or area() ?

[shane watson]

Dear Roberson!!! I have an inverse relationship between two quantities and I want to draw that relationship which is like a hyperbola. I have patch files to draw many other functions but unable to draw hyperbola with patch function thats why I am asking this question. Thank you for your reply

[Walter Roberson]

Have you considered using area() ? It creates a patch() but with a syntax that is more convenient.

[shane watson]

I have considered points on x-axis and y-axis to plot as shown in the code. Similarly, I have points to draw hyperbola. and I have no idea of area or syntax etc, as you have mentioned. Thank you, Walter Roberson.

[Walter Roberson]

Are you looking for something that draws an area, or are you looking for something that draws a curved line?

Answer 1

[KSSV]

%%hyperobola equation
% x^2/a^2-y^2/b^2=1
% hyperbola parameters
a = 1; b = 1;
% define the x-space
xmin = 5;
xmax = 5;
% convert in t-space
tmin = acosh(xmin/a);
tmax = acosh(xmax/a);
% hyperbola computation
t = linspace(-tmin,tmax,10);
x = a*cosh(t);
y = b*sinh(t);
% final plot
figure, set(gcf,'color',[1 1 1])
patch(x,y,'b')
hold on
patch(-x,y,'b')

[shane watson]

Thank you KSSV for your help.